HDU 4414 Finding crosses (DFS + BFS)】的更多相关文章

题意:在N*N的图中,找出孤立存在的十字架的个数.十字架要求为正十字,孤立表示组成十字架的‘#的周围的一格再无’#‘. dfs找出在中心的‘#’(周围四格也为‘#'),则缩小了搜索范围,再bfs找出是否是符合要求. #include <cstdio> #include <iostream> #include <cmath> #include <cstring> #include <algorithm> using namespace std; c…
题目:http://acm.hdu.edu.cn/showproblem.php?pid=4414 CSUST:点击打开链接 Finding crosses Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others) Total Submission(s): 729    Accepted Submission(s): 411 Problem Description The Nazca L…
题目链接:hdu 4414 其实是一道简单的字符型水题,不涉及任何算法,可比赛时却没能做出来,这几天的状态都差到家了... 题目大意是求有多少个满足条件的十字架,十字架的边不能有分叉路口,所以枚举每个点看是否满足条件就行,只是编码量的问题而已(感觉自己的码力不断下降了,我也不知道该怎么办好..) #include<cstdio> #include<cstring> #include<algorithm> using namespace std; ][]; int n;…
Problem Description The Nazca Lines are a series of ancient geoglyphs located in the Nazca Desert in southern Peru. They were designated as a UNESCO World Heritage Site in 1994. The high, arid plateau stretches more than 80 kilometres (50 mi) between…
Finding crosses Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others) Total Submission(s): 1631 Accepted Submission(s): 868 Problem Description The Nazca Lines are a series of ancient geoglyphs located in the Nazca Desert i…
Oil Deposits Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 15533    Accepted Submission(s): 8911 Problem Description The GeoSurvComp geologic survey company is responsible for detecting underg…
逃离迷宫 Problem Description 给定一个m × n (m行, n列)的迷宫,迷宫中有两个位置,gloria想从迷宫的一个位置走到另外一个位置,当然迷宫中有些地方是空地,gloria可以穿越,有些地方是障碍,她必须绕行,从迷宫的一个位置,只能走到与它相邻的4个位置中,当然在行走过程中,gloria不能走到迷宫外面去.令人头痛的是,gloria是个没什么方向感的人,因此,她在行走过程中,不能转太多弯了,否则她会晕倒的.我们假定给定的两个位置都是空地,初始时,gloria所面向的方向…
Problem Description Harry Potter has some precious. For example, his invisible robe, his wand and his owl. When Hogwarts school is in holiday, Harry Potter has to go back to uncle Vernon's home. But he can't bring his precious with him. As you know,…
题目链接: http://acm.hdu.edu.cn/showproblem.php?pid=4127 题目意思: 给n*n的方格,每个格子有一种颜色(0~5),每次可以选择一种颜色,使得和左上角相连(颜色相同以及相邻,间接也行)的所有的格子都为该颜色.求最少的步数,使得所有的方格颜色都相同. 解题思路: bfs+bfs死活不给过. 正确解法应该是ID(dfs+bfs).因为总共的解的步数不多. 减枝: 1.当剩余的颜色种数(至少还要这么多步)+已走的步数>设定深度时 跳出. 2.注意每次搜的…
HDU 1401 Solitaire 双向DFS 题意 给定一个\(8*8\)的棋盘,棋盘上有4个棋子.每一步操作可以把任意一个棋子移动到它周围四个方向上的空格子上,或者可以跳过它四个方向上的棋子(就像跳棋那样).给定初始状态和末状态,问能否在8步之内,从初始状态变换到末状态. 解题思路 这是是看的学长写的题解,很好,也算自己简单知道了双向BFS是什么情况了. 给定了初始状态和末状态,又有最多只能走8步的限制,所以我们很容易就可以想到进行双向BFS.但是一定要注意对冗余状态的剪枝.我们可以对这四…