乘方 思路是:pow(x,n) = pow(x,n/2)*pow(x,n-n/2) 递归实现 public double myPow(double x, int n) { if (n==0) return 1.0; else if (n>0) { double half = (double) myPow(x,n/2); if (n%2==0) return half*half; else return half*half*x; } else { if (n==Integer.MIN_VALUE)…