Given a binary search tree, write a function kthSmallest to find the kth smallest element in it. Note: You may assume k is always valid, 1 ≤ k ≤ BST's total elements. Follow up: What if the BST is modified (insert/delete operations) often and you nee…
Given a binary search tree, write a function kthSmallest to find the kth smallest element in it. Note: You may assume k is always valid, 1 ≤ k ≤ BST's total elements. Example 1: Input: root = [3,1,4,null,2], k = 1 3 / \ 1 4 \   2 Output: 1 Example 2:…
1.非递归解法 /** * Definition for a binary tree node. * struct TreeNode { * int val; * TreeNode *left; * TreeNode *right; * TreeNode(int x) : val(x), left(NULL), right(NULL) {} * }; */ class Solution { public: int kthSmallest(TreeNode* root, int k) { if(r…
给定一个二叉搜索树,编写一个函数kthSmallest来查找其中第k个最小的元素. 注意:你可以假设k总是有效的,1≤ k ≤二叉搜索树元素个数. 进阶:如果经常修改二叉搜索树(插入/删除操作)并且你需要频繁地找到第k小值呢? 你将如何优化kthSmallest函数? 详见:https://leetcode.com/problems/kth-smallest-element-in-a-bst/description/ Java实现: /** * Definition for a binary t…
题目大意 https://leetcode.com/problems/kth-smallest-element-in-a-bst/description/ 230. Kth Smallest Element in a BST Given a binary search tree, write a function kthSmallest to find the kth smallest element in it. Note: You may assume k is always valid,…
Given a binary search tree, write a function kthSmallest to find the kth smallest element in it. Note: You may assume k is always valid, 1 ≤ k ≤ BST's total elements. Follow up:What if the BST is modified (insert/delete operations) often and you need…
Given the root node of a binary search tree (BST) and a value to be inserted into the tree, insert the value into the BST. Return the root node of the BST after the insertion. It is guaranteed that the new value does not exist in the original BST. No…
题意: 寻找一棵BST中的第k小的数. 思路: 递归比较方便. /** * Definition for a binary tree node. * struct TreeNode { * int val; * TreeNode *left; * TreeNode *right; * TreeNode(int x) : val(x), left(NULL), right(NULL) {} * }; */ class Solution { public: int countNode(TreeNod…
Given a binary search tree and a node in it, find the in-order successor of that node in the BST. Note: If the given node has no in-order successor in the tree, return null. 这道题让我们求二叉搜索树的某个节点的中序后继节点,那么我们根据BST的性质知道其中序遍历的结果是有序的, 是我最先用的方法是用迭代的中序遍历方法,然后用…
Given a binary search tree and a node in it, find the in-order successor of that node in the BST. The successor of a node p is the node with the smallest key greater than p.val. Example 1: Input: root = [2,1,3], p = 1 Output: 2 Explanation: 1's in-or…