HUD-5124-lines】的更多相关文章

http://acm.hdu.edu.cn/showproblem.php?pid=5124 lines   Problem Description: John has several lines. The lines are covered on the X axis. Let A is a point which is covered by the most lines. John wants to know how many lines cover A.   Input: The firs…
题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=5124 题意:给你n段区间,他们有重合的点A,问你重合最多次的点A重合多少次 题解:对区间离散化后,维护区间最大值 #include<stdio.h> #include<string.h> #include<algorithm> #define LL long long #define MAX 100100 using namespace std; int s[MAX],e[…
http://acm.hdu.edu.cn/showproblem.php?pid=5124 题意:给你n条线段,然后找出一个被最多条线段覆盖的点,输出覆盖这个点的线段的条数. 思路:可以把一条线段分出两个端点离散化,左端点被标记为-1,右端点被标记为1,然后排序,如果遇到标记为-1,cnt++,否则cnt--;找出cnt的最大值. #include <cstdio> #include <cstring> #include <algorithm> #define max…
http://acm.hdu.edu.cn/showproblem.php?pid=5124 [题意] 在数轴x上,每次操作都覆盖一个区间的所有点,问被覆盖次数最多的点是覆盖了多少次 [思路] 最简单的扫描线,左右端点分别排序,遇到左端点sum++更新最值,遇到右端点sun--更新最值 [Accepted] #include<bits/stdc++.h> using namespace std; ],b[]; int t,n; bool cmp(int aa,int bb) { return…
http://acm.hdu.edu.cn/showproblem.php?pid=5124 lines Time Limit: 5000/2500 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 1362    Accepted Submission(s): 566 Problem Description John has several lines. The lines are…
题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=5124 题目意思:给出 n 条线段,每条线段用两个整数描述,对于第 i 条线段:xi,yi 表示该条线段的左端点和右端点.设 A 表示最多线段覆盖的点(当然这个 A 可以有多个啦,但这个无关紧要).现在需要求的是 A 被多少条线段覆盖. 我是不会做啦.......一开始还看不懂题目= = 以下是按照题解做的, 题解中的最大区间和,实际上就是求最大连续子序列的和. (1)版本1   906 MS #in…
转自:http://aigo.iteye.com/blog/2258612 蓝图脚本来处理 ================================================== 用UMG制作游戏中的物品栏(背包)-V4.8,观看需要爬梯子(这个讲的算是目前我看过的UMG教程最完整最详细的,推荐) https://wiki.unrealengine.com/Videos/Player?series=PLZlv_N0_O1gZalvQWYs8sc7RP_-8eSr3i&video=r…
http://acm.hdu.edu.cn/showproblem.php?pid=5124 Problem Description John has several lines. The lines are covered on the X axis. Let A is a point which is covered by the most lines. John wants to know how many lines cover A.   Input The first line con…
HUD——1083   Courses Time Limit: 20000/10000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 7699    Accepted Submission(s): 3781 Problem Description Consider a group of N students and P courses. Each student visits z…
关键点: <!--实现原理:要保证这两个canvas相互重叠;z-index表示了两个画布的上下层关系--> <!--是WEBGL的三维图形Canvas(主要用于绘制三维场景)--> "> Please use a browser that supports "canvas" </canvas> <!--二维的HUD的canvas(主要用于绘制HUD信息)--> "></canvas> js核心…