Java for LeetCode 145 Binary Tree Postorder Traversal

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Java for LeetCode 145 Binary Tree Postorder Traversal

Given a binary tree, return the postorder traversal of its nodes' values. For example: Given binary tree {1,#,2,3}, 1 \ 2 / 3 return [3,2,1]. 后序遍历,左子树→右子树→根节点前序遍历的非递归实现需要一个计数器,方法是需要重写一个类继承TreeNode,翁慧玉教材<数据结构:题解与拓展>P113有详细介绍,这里略.递归JAVA实现如下: public L…

C++版 - LeetCode 145: Binary Tree Postorder Traversal(二叉树的后序遍历，迭代法)

145. Binary Tree Postorder Traversal Total Submissions: 271797 Difficulty: Hard 提交网址: https://leetcode.com/problems/binary-tree-postorder-traversal/ Given a binary tree, return the postorder traversal of its nodes' values. For example:Given binary tr…

(二叉树递归) leetcode 145. Binary Tree Postorder Traversal

Given a binary tree, return the postorder traversal of its nodes' values. Example: Input: [1,null,2,3] 1 \ 2 / 3 Output: [3,2,1] Follow up: Recursive solution is trivial, could you do it iteratively? --------------------------------------------------…

LeetCode 145 Binary Tree Postorder Traversal（二叉树的兴许遍历）+（二叉树、迭代）

翻译给定一个二叉树.返回其兴许遍历的节点的值. 比如: 给定二叉树为 {1. #, 2, 3} 1 \ 2 / 3 返回 [3, 2, 1] 备注:用递归是微不足道的,你能够用迭代来完毕它吗? 原文 Given a binary tree, return the postorder traversal of its nodes' values. For example: Given binary tree {1,#,2,3}, 1 \ 2 / 3 return [3,2,1]. Note: R…

[LeetCode] 145. Binary Tree Postorder Traversal 二叉树的后序遍历

Given a binary tree, return the postorder traversal of its nodes' values. For example: Given binary tree {1,#,2,3}, 1 \ 2 / 3 return [3,2,1]. Note: Recursive solution is trivial, could you do it iteratively? 经典题目,求二叉树的后序遍历的非递归方法,跟前序,中序,层序一样都需要用到栈,后序的…

leetcode 145. Binary Tree Postorder Traversal ----- java

Given a binary tree, return the postorder traversal of its nodes' values. For example:Given binary tree {1,#,2,3}, 1 \ 2 / 3 return [3,2,1]. Note: Recursive solution is trivial, could you do it iteratively? 求后序遍历,要求不使用递归. 使用栈,从后向前添加. /** * Definition…

LeetCode 145. Binary Tree Postorder Traversal 二叉树的后序遍历 C++

Given a binary tree, return the postorder traversal of its nodes' values. Example: Input: [,,] \ / Output: [,,] Follow up: Recursive solution is trivial, could you do it iteratively? 方法一:利用两个栈s1,s2来实现,先将头结点入栈s1,从s1弹出栈顶节点记为cur,压入s2中,分别将cur的左右孩子压入s1,当s…

LeetCode 145. Binary Tree Postorder Traversal二叉树的后序遍历 (C++)

题目: Given a binary tree, return the postorder traversal of its nodes' values. Example: Input: [1,null,2,3] 1 \ 2 / 3 Output: [3,2,1] Follow up: Recursive solution is trivial, could you do it iteratively? 分析: 给定一棵二叉树,返回后序遍历. 递归方法很简单,即先访问左子树,再访问右子树,最后访…

Leetcode#145 Binary Tree Postorder Traversal

原题地址递归写法谁都会,看看非递归写法. 对于二叉树的前序和中序遍历的非递归写法都很简单,只需要一个最普通的栈即可实现,唯独后续遍历有点麻烦,如果不借助额外变量没法记住究竟遍历了几个儿子.所以,最直接的想法就是在栈中记录到底遍历了几个儿子. 代码: vector<int> postorderTraversal(TreeNode *root) { vector<int> path; stack<pair<TreeNode *, int> > st; st.p…

二叉树前序、中序、后序非递归遍历 144. Binary Tree Preorder Traversal 、 94. Binary Tree Inorder Traversal 、145. Binary Tree Postorder Traversal 、173. Binary Search Tree Iterator

144. Binary Tree Preorder Traversal 前序的非递归遍历:用堆来实现如果把这个代码改成先向堆存储左节点再存储右节点,就变成了每一行从右向左打印如果用队列替代堆,并且先存储左节点,再存储右节点,就变成了逐行打印 class Solution { public: vector<int> preorderTraversal(TreeNode* root) { vector<int> result; if(root == NULL) return res…

【LeetCode】145. Binary Tree Postorder Traversal (3 solutions)

Binary Tree Postorder Traversal Given a binary tree, return the postorder traversal of its nodes' values. For example:Given binary tree {1,#,2,3}, 1 \ 2 / 3 return [3,2,1]. Note: Recursive solution is trivial, could you do it iteratively? 解法一:递归法 /**…

145. Binary Tree Postorder Traversal

题目: Given a binary tree, return the postorder traversal of its nodes' values. For example:Given binary tree {1,#,2,3}, 1 \ 2 / 3 return [3,2,1]. Note: Recursive solution is trivial, could you do it iteratively? 链接: http://leetcode.com/problems/binary…

【LeetCode】145. Binary Tree Postorder Traversal 解题报告 (C++&Python)

作者: 负雪明烛 id: fuxuemingzhu 个人博客:http://fuxuemingzhu.cn/ 目录题目描述题目大意解题方法递归迭代日期题目地址:https://leetcode.com/problems/binary-tree-postorder-traversal/ 题目描述 Given a binary tree, return the postorder traversal of its nodes' values. Example: Input: [1,nu…

LeetCode OJ 145. Binary Tree Postorder Traversal

Given a binary tree, return the postorder traversal of its nodes' values. For example:Given binary tree {1,#,2,3}, 1 \ 2 / 3 return [3,2,1]. Note: Recursive solution is trivial, could you do it iteratively? Subscribe to see which companies asked this…

【LeetCode】145. Binary Tree Postorder Traversal

Difficulty: Hard More:[目录]LeetCode Java实现 Description https://leetcode.com/problems/binary-tree-postorder-traversal/ Given a binary tree, return the postordertraversal of its nodes' values. Example: Input: [1,null,2,3] 1 \ 2 / 3 Output: [3,2,1] Foll…

【leetcode】Binary Tree Postorder Traversal

题目: Given a binary tree, return the postorder traversal of its nodes' values. For example: Given binary tree {1,#,2,3}, 1 \ 2 / 3 return [3,2,1]. Note: Recursive solution is trivial, could you do it iteratively? 例如以下列出三种解法:一种迭代的和两种iterative的 import j…

Java for LeetCode 144 Binary Tree Preorder Traversal

Given a binary tree, return the preorder traversal of its nodes' values. For example: Given binary tree {1,#,2,3}, 1 \ 2 / 3 return [1,2,3]. 二叉树的前序遍历,根节点→左子树→右子树解题思路一: 递归实现,JAVA实现如下: public List<Integer> preorderTraversal(TreeNode root) { List<I…

leetcode题解:Binary Tree Postorder Traversal (二叉树的后序遍历)

题目: Given a binary tree, return the postorder traversal of its nodes' values. For example:Given binary tree {1,#,2,3}, 1 \ 2 / 3 return [3,2,1]. Note: Recursive solution is trivial, could you do it iteratively? 说明: 1) 两种实现,递归与非递归 , 其中非递归有两种方法 2)复杂度分析…