P2979 [USACO10JAN]奶酪塔Cheese Towers 背包dp 不过多了一个大奶酪可以压扁其他奶酪的 一开始写了个暴力82分.贪心的选择 然后发现,有如下两种规律 要么最优都是小奶酪,要么就是有一个大奶酪是在顶上的. 所以我们先用小奶酪跑一遍背包,记录最优值. 然后加上大奶酪,不考虑压缩的再跑一遍.因为如果大奶酪在上面的话,我们就不用考虑在dp中压缩,直接跑完dp后.看做一大块一起压缩 #include<iostream> #include<algorithm> #…

P2979 [USACO10JAN]奶酪塔Cheese Towers 题目描述 Farmer John wants to save some blocks of his cows' delicious Wisconsin cheese varieties in his cellar for the coming winter. He has room for one tower of cheese in his cellar, and that tower's height can be at…

题目描述 Farmer John wants to save some blocks of his cows' delicious Wisconsin cheese varieties in his cellar for the coming winter. He has room for one tower of cheese in his cellar, and that tower's height can be at most T (1 <= T <= 1,000). The cows…

做数论都做傻了,这道题目 有推荐,当时的分类放在了递推里面,然后我就不停的去推啊推啊,后来推出来了,可是小一点的数 输出答案都没问题,大一点的数 输出答案就是错的,实在是不知道为什么,后来又不停的看,突然有股傻眼的感觉,这个貌似很面善很面熟啊,不禁想起以前一到背包题目,也是给了具体数字 最大范围,最后使用背包来解决的,那么这道有些相似,后来翻了 背包九讲的PDF,我了个去,这不就是 完全背包么? 恨死!!!一定要牢牢记住!!! 有N种物品和一个容量为V的背包,每种物品都有无限件可用. 第i种物品…

题目传送门 Strange Towers of Hanoi Time Limit: 1000MS   Memory Limit: 30000K Total Submissions: 3117   Accepted: 2004 Description Background Charlie Darkbrown sits in another one of those boring Computer Science lessons: At the moment the teacher just exp…

题目链接:http://www.lydsy.com/JudgeOnline/problem.php?id=1677 题意: 给定n(n <= 10^6),将n分解为2的幂次方之和,问你有多少种方法. 题解: 两种方法. 一.无限背包 将1,2,4,8...看作物品体积就好. 复杂度O(n*k),k约为20. 二.递推 对于dp[i],有两种情况. (1)i为奇数.则分解结果中一定有1. 所以dp[i] = dp[i-1]. (2)i为偶数.再分两种情况: a. 分解结果中有1,所以dp[i] +…

Sumsets Time Limit: 2000MS   Memory Limit: 200000K Total Submissions: 20315   Accepted: 7930 Description Farmer John commanded his cows to search for different sets of numbers that sum to a given number. The cows use only numbers that are an integer…

2021: [Usaco2010 Jan]Cheese Towers Time Limit: 4 Sec  Memory Limit: 64 MBSubmit: 184  Solved: 107[Submit][Status] Description Farmer John wants to save some blocks of his cows' delicious Wisconsin cheese varieties in his cellar for the coming winter.…

题目链接:点击进入 题目分析: 简单的组合背包模板题,但是递推的同时要刷新这种情况使用了哪些物品 ac代码: #include<bits/stdc++.h> using namespace std; ],zhu[],t[]; struct student { int s; int number; ]; }f[][]; int main() { std::ios::sync_with_stdio(false); int m,v,n;//m总重量,v总阻力,n物品数 cin>>m>…

题目链接:P2347 砝码称重 参考题解:点击进入 纪念我第一道没理解题意的题 ''但不包括一个砝码也不用的情况'',这句话我看成了每个砝码起码放一个 然后就做不出来了 思路: 1.这题数据很小,1000,所以其实没必要把多重背包用二进制优化成01背包,直接一个个拆开就好了 2.建立数组f[2000],用来f[j]=1表示存在重量为j这种可能,f[j]=0则表示不存在这种可能 建立数组a[2000],用来把多重背包一个个拆开 比如说我们输入的是 0 0 那a就是{,} 数组f其实是用了"桶&qu…