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Description You are planning to build housing on a street. There are n spots available on the street on which you can build a house. The spots are labeled from 1 to n from left to right. In each spot, you can build a house with an integer height betw…
CF1146G Zoning Restrictions 网络流 h<=50? 直接都选择最大的,ans=n*h*h 最小割 考虑舍弃或者罚款 有一个>x就要罚款? 经典取值限制的模型:切糕割! 每个位置的x+1到额外点tot连接inf边 tot向t连接c边 大概这样: #include<bits/stdc++.h> #define reg register int #define il inline #define fi first #define se second #defin…
A. Zoning Restrictions Again ou are planning to build housing on a street. There are n spots available on the street on which you can build a house. The spots are labeled from 1 to n from left to right. In each spot, you can build a house with an int…
Forethought Future Cup - Elimination Round 窝也不知道这是个啥比赛QwQ A. Love "A" 给你一个串,你可以删去若干个元素,使得最后a的个数严格大于一半.求最大串长. #include<iostream> #include<cstdio> #include<cstring> using namespace std; char s[55];int v=0,n; int main() { scanf(&q…
CF1155D - Beautiful Array 题意:给你一个序列和x,你可以选择任意一个子串(可以为空)乘上x,使得得到的序列最大子串和最大.求这个最大值.30w,2s. 解:设fi,0/1/2表示序列前i个数还没乘x/正在乘x/乘完了x的最大后缀和.答案就是这个DP数组的最大值. #include <bits/stdc++.h> typedef long long LL; ; LL a[N], x, f[N][]; int n; int main() { scanf("%d%…
方法说明 方法 说明 Restrictions.eq = Restrictions.allEq 利用Map来进行多个等于的限制 Restrictions.gt > Restrictions.ge >= Restrictions.lt < Restrictions.le <= Restrictions.between BETWEEN Restrictions.like LIKE Restrictions.in in Restrictions.and and Restrictions.…
The form below uses HTML form field restrictions. In order to pass this lesson, submit the form with each field containing an unallowed value. You must submit invalid values for all six fields in one form submission. 1.这个习题如果直接用burp拦截提交请求后,发现Disabled…
在用新浪微博授权第三方app时,授权失败,log显示 com.sina.weibo.sdk.exception.WeiboHttpException: {,"request":"/2/users/show.json"} at com.sina.weibo.sdk.net.HttpManager.requestHttpExecute(HttpManager.java:) at com.sina.weibo.sdk.net.HttpManager.openUrl(Htt…
HQL运算符 QBC运算符 含义 = Restrictions.eq() 等于equal <>  Restrictions.ne() 不等于not equal >  Restrictions.gt() 大于greater than >= Restrictions.ge() 大于等于greater than or equal <  Restrictions.lt() 小于less than <= Restrictions.le() 小于等于less than or equ…
方法说明 方法 说明 Restrictions.eq = Restrictions.allEq 利用Map来进行多个等于的限制 Restrictions.gt > Restrictions.ge >= Restrictions.lt < Restrictions.le <= Restrictions.between BETWEEN Restrictions.like LIKE Restrictions.in in Restrictions.and and Restrictions.…