1001.Alice and Bob 签到题*1,只要x * 2 == n && y * 2 == m就满足条件. var m, n, x, y : int64; begin while not eof do begin readln(m, n, x, y); * x) * y) then writeln('YES') else writeln('NO'); end; end. 1002.Bob and math problem 我真是WA的不行,但是很明显我的算法没有问题啊... (20…
HDOJ5054 Alice and Bob Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others) Total Submission(s): 302 Accepted Submission(s): 229 Problem Description Bob and Alice got separated in the Square, they agreed that if they…
题目链接: huangjing hdu5054 Alice and Bob 思路: 就是(x,y)在两个參考系中的表示演全然一样.那么仅仅可能在这个矩形的中点.. 题目: Alice and Bob Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others) Total Submission(s): 216 Accepted Submission(s): 166 Problem De…
太菜,仅仅能去Div2.(都做不完 ORZ... 各自是 HDU: 5054pid=5054"> Alice and Bob 5055Bob and math problem 5056Boring count 5057pid=5057"> Argestes and Sequence # 1001 碰面仅仅能在坐标中间. 所以推断一下就好了. #include<cstdio> #include<cstring> #include<string&g…
BestCoder Round #7 Start Time : 2014-08-31 19:00:00 End Time : 2014-08-31 21:00:00Contest Type : Register Public Contest Status : Ended Current Server Time : 2014-08-31 21:12:12 Solved Pro.ID Title Ratio(Accepted / Submitted) 1001 Little Pony…
BestCoder Round #90 A Kblack loves flag 题意有点迷不造思路很简单但不造怎么求随机数,纠结了一会后直接粘上题目所给的代码稍加修改A了. const int _K=50268147,_B=6082187,_P=100000007; int _X; inline int get_rand(int _l,int _r){ _X=((long long)_K*_X+_B)%_P; return _X%(_r-_l+1)+_l; } int n,m,k,seed,x…
tree Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/65536 K (Java/Others)Total Submission(s): 863 Accepted Submission(s): 409 Problem Description There is a tree(the tree is a connected graph which contains n points and n−1 edges),t…
