这题一眼看就是水题,map随便计 然后我之所以发这个题解,是因为我用了log2()这个函数判断在哪一层 我只能说我真是太傻逼了,这个函数以前听人说有精度问题,还慢,为了图快用的,没想到被坑惨了,以后尽量不用 #include <cstdio> #include <cstdlib> #include <cstring> #include <cmath> #include <iostream> #include <algorithm> #…

题目链接: A. Lorenzo Von Matterhorn time limit per test 1 second memory limit per test 256 megabytes input standard input output standard output Barney lives in NYC. NYC has infinite number of intersections numbered with positive integers starting from 1…

题目链接: http://codeforces.com/problemset/problem/696/A 题目大意: 一个满二叉树,深度无限,节点顺序编号,k的儿子是k+k和k+k+1,一开始树上的边权都为0 N(N<=1000)个操作,操作两种,1是从u到v的路径上的所有边权+w,2是求u到v的边权和.(1 ≤ v, u ≤ 1018, v ≠ u, 1 ≤ w ≤ 109) 题目思路: [STL][模拟] 用map写很快,第一次用很生疏.现学只看了一点点. 因为是满二叉树所以直接暴力求LCA…

方法:求出最近公共祖先,使用map给他们计数,注意深度的求法. 代码如下: #include<iostream> #include<cstdio> #include<map> #include<cstring> using namespace std; #define LL long long map<LL,LL> sum; int Get_Deep(LL x) { ; i < ; i++) { ))>x) ; } ; } void…

http://codeforces.com/contest/697/problem/C C. Lorenzo Von Matterhorn time limit per test 1 second memory limit per test 256 megabytes input standard input output standard output Barney lives in NYC. NYC has infinite number of intersections numbered…

2018-03-16 http://codeforces.com/problemset/problem/697/C C. Lorenzo Von Matterhorn time limit per test 1 second memory limit per test 256 megabytes input standard input output standard output Barney lives in NYC. NYC has infinite number of intersect…

原题链接:http://codeforces.com/contest/696/problem/A 原题描述: Lorenzo Von Matterhorn   Barney lives in NYC. NYC has infinite number of intersections numbered with positive integers starting from 1. There exists a bidirectional road between intersections i a…

Lorenzo Von Matterhorn Barney lives in NYC. NYC has infinite number of intersections numbered with positive integers starting from 1. There exists a bidirectional road between intersections i and 2i and another road between i and 2i + 1 for every pos…

C. Lorenzo Von Matterhorn time limit per test 1 second memory limit per test 256 megabytes input standard input output standard output Barney lives in NYC. NYC has infinite number of intersections numbered with positive integers starting from 1. Ther…

Lorenzo Von Matterhorn time limit per test 1 second memory limit per test 256 megabytes input standard input output standard output Barney lives in NYC. NYC has infinite number of intersections numbered with positive integers starting from 1. There e…

A. Lorenzo Von Matterhorn time limit per test 1 second memory limit per test 256 megabytes input standard input output standard output Barney lives in NYC. NYC has infinite number of intersections numbered with positive integers starting from 1. Ther…

题目链接: B. Modulo Sum time limit per test 2 seconds memory limit per test 256 megabytes input standard input output standard output You are given a sequence of numbers a1, a2, ..., an, and a number m. Check if it is possible to choose a non-empty subse…

A.Beru-taxi 水题:有一个人站在(sx,sy)的位置,有n辆出租车,正向这个人匀速赶来,每个出租车的位置是(xi, yi) 速度是 Vi;求人最少需要等的时间: 单间循环即可: #include<iostream> #include<algorithm> #include<string.h> #include<stdio.h> #include<math.h> #include<vector> using namespace…

题意:给定 n 和 k,然后是 n 个数,表示1-k的一个值,问你修改最少的数,使得所有的1-k的数目都等于n/k. 析:水题,只要用每个数减去n/k,然后取模,加起来除以2,就ok了. 代码如下: #pragma comment(linker, "/STACK:1024000000,1024000000") #include <cstdio> #include <string> #include <cstdlib> #include <cma…

Problem G.Giant ScreenTime Limit: 20 Sec Memory Limit: 256 MB 题目连接 http://acm.hust.edu.cn/vjudge/contest/view.action?cid=86821#problem/G Description You are working in Advanced Computer Monitors (ACM), Inc. The company is building and selling giant c…

题目链接: A. King Moves 题意: 给出king的位置,问有几个可移动的位置; 思路: 水题,没有思路; AC代码: #include <iostream> #include <cstdio> #include <cstring> #include <algorithm> #include <cmath> #include <bits/stdc++.h> #include <stack> #include &l…

题目链接: A. Round House time limit per test 1 second memory limit per test 256 megabytes input standard input output standard output Vasya lives in a round building, whose entrances are numbered sequentially by integers from 1 to n. Entrance n and entra…

B. BerSU Ball time limit per test 1 second memory limit per test 256 megabytes input standard input output standard output The Berland State University is hosting a ballroom dance in celebration of its 100500-th anniversary! n boys and m girls are al…

题目链接: A. Maximum Increase time limit per test 1 second memory limit per test 256 megabytes input standard input output standard output You are given array consisting of n integers. Your task is to find the maximum length of an increasing subarray of…

A,给一棵完全二叉树,第一个操作,给两个点,两点路径上的所有边权值都增加w,第二个操作,给两个点,求两点路径上的所有边权值和. 我看一眼题就觉得是树链剖分,而我又不会树链剖分,扔掉. 后来查了题解,首先数据范围是1e18不可能是树剖,其次完全二叉树啊!不是普通的树啊!!sb... //我做过此题,没做出来,被学弟教会..虽然我做的题少,但我一向觉得至少自己做过的题都是记得的...但是.... #include <algorithm> #include <iostream> #inc…

题目链接:http://codeforces.com/problemset/problem/697/D 给你一个有规则的二叉树,大概有1e18个点. 有两种操作:1操作是将u到v上的路径加上w,2操作是求u到v上的路径和. 我们可以看出任意一个点到1节点的边个数不会超过64(差不多就是log2(1e18)),所以可以找最近相同祖节点的方式写. 用一条边的一个唯一的端点作为边的编号(比如1到2,那2就为这条边的编号),由于数很大,所以用map来存. 进行1操作的时候就是暴力加w至u到LCA(u,v…

Least Common Ancestors 节点范围是1~1e18,至多1000次询问. 只要不断让深的节点退一层(>>1)就能到达LCA. 用点来存边权,用map储存节点和父亲连边的权值. #include<cstdio> #include<map> #define ll long long using namespace std; map<ll,ll>m; ll u,v,w; void add(){ while(u!=v){ if(u<v){ m…

C. CinderellaTime Limit: 20 Sec Memory Limit: 256 MB 题目连接 http://codeforces.com/gym/100685/problem/C Description Cinderella is given a task by her Stepmother before she is allowed to go to the Ball. There are N (1 ≤ N ≤ 1000) bottles with water in th…

题目链接:http://codeforces.com/problemset/problem/44/E 题意: 给一个字符串,让你分割成 $k$ 行,每行的字母数在 $[a,b]$ 之间. 题解: 这是1500difficulty的DP题? AC代码: #include<bits/stdc++.h> using namespace std; int k,a,b; string s; int main() { cin>>k>>a>>b; cin>>s…

题意:给定两个相同长度的字符串,让你找出一个字符串,字典序在两都之间. 析:这个题当时WA了好多次,后来才发现是这么水,我们只要把 s 串加上,然后和算数一样,该进位进位,然后再和 t 比较就行. 代码如下: #include <iostream> #include <cstdio> #include <algorithm> #include <vector> #include <set> #include <cstring> #in…

原题链接:http://codeforces.com/gym/100431/attachments/download/2421/20092010-winter-petrozavodsk-camp-andrew-stankevich-contest-37-asc-37-en.pdf 题意 神奇的电路可以通过比较器来实现冒泡. 题解 倒着往回考虑,搞搞就好. 代码 #include<iostream> #include<cstdio> #include<cstring> #…

题目链接:http://codeforces.com/problemset/problem/710/A 题目大意:在一个棋盘中给出一个位置,判断该位置周围8个点还有几个点可以摆放棋子. AC代码解释解法: #include<bits/stdc++.h> using namespace std; int main() { char c; int x,y; while(~scanf("%c%d",&c,&x)) { getchar(); y=c-; &&…

题意:给定一个字符串,让你把它的一个子串字符都减1,使得总字符串字典序最小. 析:由于这个题是必须要有一个字串,所以你就要注意这个只有一个字符a的情况,其他的就从开始减 1,如果碰到a了就不减了,如果到最后一位了还没开始减, 就减最后一位. 代码如下: #pragma comment(linker, "/STACK:1024000000,1024000000") #include <cstdio> #include <string> #include <c…

B. Island Time Limit: 1 Sec Memory Limit: 256 MB 题目连接 http://codeforces.com/gym/100114 Description On February 30th this year astronauts from the International Space Station flew over the Pacific Ocean and took a picture, on which was discovered a pr…

题目链接:https://codeforces.com/contest/1090/problem/A A conglomerate consists of n companies. To make managing easier, their owners have decided to merge all companies into one. By law, it is only possible to merge two companies, so the owners plan to s…