传送门: http://acm.hdu.edu.cn/showproblem.php?pid=1005 Number Sequence Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 198316 Accepted Submission(s): 49744 Problem Description A number sequence…
Number Sequence Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others) Total Submission(s): 86102 Accepted Submission(s): 20423 Problem Description A number sequence is defined as follows: f(1) = 1, f(2) = 1, f(n) = (A * f(n…
A number sequence is defined as follows: f(1) = 1, f(2) = 1, f(n) = (A * f(n - 1) + B * f(n - 2)) mod 7. Given A, B, and n, you are to calculate the value of f(n). InputThe input consists of multiple test cases. Each test case contains 3 integers A,…
Number Sequence Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others) Total Submission(s): 176080 Accepted Submission(s): 43527 Problem Description A number sequence is defined as follows: f(1) = 1, f(2) = 1, f(n) = (…
f(n-1)和f(n-2)所有组合都49种子,这期可达49,但f(n-1)=f(n-2)=0如果是,列的总数目0.话题条件f(1)=f(2)=1.因此排除这样的情况.的最长期限48. #include<math.h> #include<stdio.h> #include<stdlib.h> #include<string.h> int main(void) { int a,b,n; int f[99]; while(scanf("%d%d%d&qu…
Number Sequence Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 187893 Accepted Submission(s): 46820 Problem Description A number sequence is defined as follows: f(1) = 1, f(2) = 1, f(n) = (A…
Number Sequence Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others) Total Submission(s): 124827 Accepted Submission(s): 30331 Problem Description A number sequence is defined as follows: f(1) = 1, f(2) = 1, f(n) = (A * f(…
HDU 1005 Number Sequence(数列) Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others) [Description] [题目描述] A number sequence is defined as follows: f(1) = 1, f(2) = 1, f(n) = (A * f(n - 1) + B * f(n - 2)) mod 7. Given A, B, an…
Problem Description A number sequence is defined as follows: f(1) = 1, f(2) = 1, f(n) = (A * f(n - 1) + B * f(n - 2)) mod 7. Given A, B, and n, you are to calculate the value of f(n). Input The input consists of multiple test cases. Each test case…