【POJ3784】Running Median】的更多相关文章

Running Median Time Limit: 1000MS   Memory Limit: 65536K Total Submissions: 3406   Accepted: 1576 Description For this problem, you will write a program that reads in a sequence of 32-bit signed integers. After each odd-indexed value is read, output…
Running Median Description For this problem, you will write a program that reads in a sequence of 32-bit signed integers. After each odd-indexed value is read, output the median (middle value) of the elements received so far. Input The first line of…
[题目链接] http://poj.org/problem?id=3784 [算法] 对顶堆算法 要求动态维护中位数,我们可以将1-M/2(向下取整)小的数放在大根堆中,M/2+1-M小的数放在小根堆中 每次插入元素时,先将插入元素与小根堆堆顶比较,如果比堆顶小,则插入小根堆,否则,插入大根堆,然后,判断两个堆 的元素个数是否平衡,若不平衡,则交换两个堆的堆顶 [代码] #include <algorithm> #include <bitset> #include <ccty…
[题意] 给两个有序数组,寻找两个数组组成后的中位数,要求时间复杂度为O(log(n+m)). [题解] 感觉这道题想法非常妙!! 假定原数组为a,b,数组长度为lena,lenb. 那么中位数一定是第k = (lena + lenb + 1)/ 2小的数,如果是数组长度和是偶数的话就是第k = (lena + lenb + 1)/ 2小和第k = (lena + lenb + 2)/ 2小的数,所以我们可以把问题转化为求第k小的数. 然后分别对a,b找第k / 2小的数,假如a[k / 2 -…
Given an increasing sequence S of N integers, the median is the number at the middle position. For example, the median of S1={11, 12, 13, 14} is 12, and the median of S2={9, 10, 15, 16, 17} is 15. The median of two sequences is defined to be the medi…
题目描述: There are two sorted arrays nums1 and nums2 of size m and n respectively. Find the median of the two sorted arrays. The overall run time complexity should be O(log (m+n)). 解题思路: 这道题个人觉得是很难的,要想解出这个题,就必须了解一下几点: 1.求一列长度为len的数字的中位数,其实也可以被看做是求第len/2…
There are two sorted arrays nums1 and nums2 of size m and n respectively. Find the median of the two sorted arrays. The overall run time complexity should be O(log (m+n)). Example 1: nums1 = [1, 3] nums2 = [2] The median is 2.0 Example 2: nums1 = [1,…
There are two sorted arrays nums1 and nums2 of size m and n respectively. Find the median of the two sorted arrays. The overall run time complexity should be O(log (m+n)). You may assume nums1 and nums2 cannot be both empty. Example 1: nums1 = [1, 3]…
模的是这位神犇的代码:Atcoder AGC012F : Prefix Median 题意: 在动态中位数那道题上做了一些改动.给你一个序列a,可以将a重新任意排序,然后对于a序列构造出b序列. 假设a序列有2*n-1个元素,b序列有n个元素. 其中b[i]=Median(a[1],a[2],a[3]...a[2i-1]).求能够构造出多少个不同的b序列. 数据范围: 1<=N<=50,1<=ai<=2N-1 思路: 这道题真的是究极神题...虽然说代码实现比较简单,但是分析的过程…
Median of Two Sorted Arrays There are two sorted arrays A and B of size m and n respectively. Find the median of the two sorted arrays. The overall run time complexity should be O(log (m+n)). 解法一:保底做法,O(m+n)复杂度 按照归并排序的思路,先归并,再找中间值. class Solution { p…