题目:在一个数组中,除了两个数外,其余数都是两两成对出现,找出这两个数,要求时间复杂度O(n),空间复杂度O(1) 分析:这道题考察位操作:异或(^),按位与(&),移位操作(>>, <<)等,Java代码及注释如下: public static int[] findTwoSingleNum(int[] num) { int[] twoNums = new int[2]; int result = 0; for (int i = 0; i < num.length;…
#include <iostream>#include <algorithm>//#include <vector>using namespace std; int main () { int myints[] = {32,71,12,45,26,67,53,68}; int l=sizeof(myints)/sizeof(myints[0]);//数组长度 int N=100; sort (myints, myints+l); int myints2 [8]; for…