每日一题力扣 445 https://leetcode.cn/problems/add-two-numbers-ii/

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LeetCode 题解之Add Two Numbers II

1.题目描述 2.分析首先将链表翻转,然后做加法. 最后将结果链表翻转. 3.代码 ListNode* addTwoNumbers(ListNode* l1, ListNode* l2) { ListNode* L1 = reverseList( l1 ); ListNode* L2 = reverseList( l2 ); ListNode* head = ); ListNode* result = head; ListNode* p1 = L1; ListNode* p2 = L2; ;…

[LeetCode] 445. Add Two Numbers II 两个数字相加之二

You are given two linked lists representing two non-negative numbers. The most significant digit comes first and each of their nodes contain a single digit. Add the two numbers and return it as a linked list. You may assume the two numbers do not con…

LeetCode 445. 两数相加 II(Add Two Numbers II)

445. 两数相加 II 445. Add Two Numbers II 题目描述给定两个非空链表来代表两个非负整数.数字最高位位于链表开始位置.它们的每个节点只存储单个数字.将这两数相加会返回一个新的链表. 你可以假设除了数字 0 之外,这两个数字都不会以零开头. 进阶: 如果输入链表不能修改该如何处理?换句话说,你不能对列表中的节点进行翻转. LeetCode445. Add Two Numbers II中等示例: 输入: (7 -> 2 -> 4 -> 3) + (5 ->…

【LeetCode】445. Add Two Numbers II 解题报告（Python & C++）

作者: 负雪明烛 id: fuxuemingzhu 个人博客: http://fuxuemingzhu.cn/ 目录题目描述题目大意解题方法先求和再构成列表使用栈保存节点数字类似题目日期题目地址:https://leetcode.com/problems/add-two-numbers-ii/description/ 题目描述 You are given two non-empty linked lists representing two non-negative intege…

445. Add Two Numbers II - LeetCode

Question 445. Add Two Numbers II Solution 题目大意:两个列表相加思路:构造两个栈,两个列表的数依次入栈,再出栈的时候计算其和作为返回链表的一个节点 Java实现: public ListNode addTwoNumbers(ListNode l1, ListNode l2) { Stack<Integer> s1 = new Stack<>(); Stack<Integer> s2 = new Stack<>();…

LeetCode Add Two Numbers II

原题链接在这里:https://leetcode.com/problems/add-two-numbers-ii/ 题目: You are given two linked lists representing two non-negative numbers. The most significant digit comes first and each of their nodes contain a single digit. Add the two numbers and return…

leetcode@ [2/43] Add Two Numbers / Multiply Strings(大整数运算)

https://leetcode.com/problems/multiply-strings/ Given two numbers represented as strings, return multiplication of the numbers as a string. Note: The numbers can be arbitrarily large and are non-negative. class Solution { public: string multiply(stri…