LeetCode No.166,167,168】的更多相关文章

No.166 FractionToDecimal 分数到小数 题目 给定两个整数,分别表示分数的分子 numerator 和分母 denominator,以字符串形式返回小数. 如果小数部分为循环小数,则将循环的部分括在括号内. 示例 输入: numerator = 1, denominator = 2 输出: "0.5" 输入: numerator = 2, denominator = 1 输出: "2" 输入: numerator = 2, denominato…
LeetCode Contest 166 第一次知道LeetCode 也有比赛. 很久没有打过这种线上的比赛,很激动. 直接写题解吧 第一题 很弱智 class Solution { public: int subtractProductAndSum(int n) { int num1=0; int num2=1; while(n) { int x = n%10; num1+=x; num2*=x; n/=10; } return num2-num1; } }; 第二题 也很简单的,我先排个序.…
[LeetCode]166. Fraction to Recurring Decimal 解题报告(Python) 标签(空格分隔): LeetCode 作者: 负雪明烛 id: fuxuemingzhu 个人博客: http://fuxuemingzhu.cn/ 题目地址:https://leetcode.com/problems/fraction-to-recurring-decimal/description/ 题目描述: Given two integers representing t…
Given an array of integers that is already sorted in ascending order, find two numbers such that they add up to a specific target number. The function twoSum should return indices of the two numbers such that they add up to the target, where index1 m…
Fraction to Recurring Decimal Given two integers representing the numerator and denominator of a fraction, return the fraction in string format. If the fractional part is repeating, enclose the repeating part in parentheses. For example, Given numera…
题目 Given two integers representing the numerator and denominator of a fraction, return the fraction in string format. If the fractional part is repeating, enclose the repeating part in parentheses. For example, Given numerator = 1, denominator = 2, r…
Description Given an array of integers that is already sorted in ascending order, find two numbers such that they add up to a specific target number. The function twoSum should return indices of the two numbers such that they add up to the target, wh…
Fraction to Recurring Decimal Given two integers representing the numerator and denominator of a fraction, return the fraction in string format. If the fractional part is repeating, enclose the repeating part in parentheses. Example 1: Input: numerat…
LeetCode题目解答——Easy部分 Posted on 2014 年 11 月 3 日 by 四火 [Updated on 9/22/2017] 如今回头看来,里面很多做法都不是最佳的,有的从复杂度上根本就不是最优解,有的写的太啰嗦,有的则用了一些过于tricky的方法.我没有为了这个再更新,就让它们去吧. LeetCode最近很火,我以前不太知道有这么一个很方便练习算法的网站,直到大概数周前同事和我说起,正好我老婆要找工作,而根据同事的理论,LeetCode的题目是必须攻破的第一道关卡.…
剑指offer 重建二叉树 提交网址: http://www.nowcoder.com/practice/8a19cbe657394eeaac2f6ea9b0f6fcf6?tpId=13&tqId=11157 或 leetcode 105: https://leetcode.com/problems/construct-binary-tree-from-preorder-and-inorder-traversal/ 参与人数:5246  时间限制:1秒  空间限制:32768K 题目描述 输入某…