Besides heap, multiset<int> can also be used: class Solution { void removeOnly1(multiset<int> &ms, int v) { auto pr = ms.equal_range(v); ms.erase(pr.first); } void remove(multiset<int> &lmax, multiset<int> &rmin, int v)…

Data Stream Median Numbers keep coming, return the median of numbers at every time a new number added. Have you met this question in a real interview? Example For numbers coming list: [1, 2, 3, 4, 5], return [1, 1, 2, 2, 3]. For numbers coming list:…

LintCode 81. Data Stream Median (Hard) 思路: 用一个大根堆保存较小的一半数, 一个小根堆保存较大的一半数. 每次根据num和两个堆顶的数据决定往哪个堆里面放. 放完后进行平衡确保两个堆的size差不超过1. 利用两个堆的size和堆顶值计算median. 大根堆可以表示为priority_queue<int, vector<int>, less<int>>, 其实priority_queue<int>默认就是大根堆.…

［抄题］: 数字是不断进入数组的,在每次添加一个新的数进入数组的同时返回当前新数组的中位数. ［思维问题］: ［一句话思路］: 左边x个元素,右边要有x+1个元素,因此利用maxheap把左边的最大值揪出来,利用minheap把右边的最小值揪出来 如果maxHeap.peek() > minHeap.peek(),就不断流动,直到顺滑. ［输入量］:空: 正常情况:特大:特小:程序里处理到的特殊情况:异常情况(不合法不合理的输入): ［画图］: ［一刷］: 接口类是Queue<Integer&…

原题链接在这里:http://www.lintcode.com/zh-cn/problem/sliding-window-matrix-maximum/ 题目: Given an array of n * m matrix, and a moving matrix window (size k * k), move the window from top left to botton right at each iteration, find the maximum number inside…

[题目描述] Given an array of n integer, and a moving window(size k), move the window at each iteration from the start of the array, find the median of the element inside the window at each moving. (If there are even numbers in the array, return the N/2-t…

Find Median from Data Stream Median is the middle value in an ordered integer list. If the size of the list is even, there is no middle value. So the median is the mean of the two middle value. Examples: [2,3,4] , the median is 3 [2,3], the median is…

Median is the middle value in an ordered integer list. If the size of the list is even, there is no middle value. So the median is the mean of the two middle value. Examples: [2,3,4] , the median is 3 [2,3], the median is (2 + 3) / 2 = 2.5 Given an a…

Median is the middle value in an ordered integer list. If the size of the list is even, there is no middle value. So the median is the mean of the two middle value. Examples: [2,3,4] , the median is 3 [2,3], the median is (2 + 3) / 2 = 2.5 Given an a…

中位数是有序列表中间的数.如果列表长度是偶数,中位数则是中间两个数的平均值. 例如, [2,3,4] 的中位数是 3 [2,3] 的中位数是 (2 + 3) / 2 = 2.5 设计一个支持以下两种操作的数据结构: void addNum(int num) - 从数据流中添加一个整数到数据结构中. double findMedian() - 返回目前所有元素的中位数. 示例: addNum(1) addNum(2) findMedian() -> 1.5 addNum(3) findMedian…