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http://graphics.stanford.edu/~seander/bithacks.html Bit Twiddling Hacks By Sean Eron Andersonseander@cs.stanford.edu Individually, the code snippets here are in the public domain (unless otherwise noted) — feel free to use them however you please. Th…
备份文件时看到的.我以前居然下过这东西. 2016-12-4 12:05:52更新 纯文本格式真棒.假如使用word写的我能拷过来格式还不乱?? Markdown真好. Bit Hacks By Sean Eron Anderson seander@cs.stanford.edu Converted to Markdown by Joe Gibson (@gibsjose) joseph.gibson@nasa.gov Edits and Table of Contents by Jeroen…
1.struct与typedef struct struct Student{int a;int b}stu1; //定义名为Student的结构体,及一个Student变量stu1 struct {int a;int b;}stu1; //只定义了一个结构体变量stu1,未定义结构体名,无法再定义其他变量 typedef struct Student{int a;int b;}Stu1,Stu2; //定义结构体类型为Student,别名为Stu1或Stu2,此时有三种定义相应变量的方式: s…
http://programming.sirrida.de/ Discussion topics Bit permutations Download source files List of function descriptions Online source code generator for bit permutations My proposals for Pascal My proposals for new x86 instructions Programming topics C…
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题目: Reverse bits of a given 32 bits unsigned integer. For example, given input 43261596 (represented in binary as 00000010100101000001111010011100), return 964176192 (represented in binary as00111001011110000010100101000000). Follow up:If this functi…
▶ 原文标题<Bit Twiddling Hacks>,地址:https://graphics.stanford.edu/~seander/bithacks.html ▶ 额外参考资料:https://leetcode.com/problems/sum-of-two-integers/discuss/84278/ ▶ 计算 int v 的符号放入 int sign . // 方法零,(v >= 0) ? 0 : -1; sign = -(v < ); // 方法一,(v >=…
问题 什么是例如最好的算法,下面的转换? 0010 0000 => 0000 0100 从详细的转换MSB->LSB至LSB->MSB, 所有的Bit必须扭转,着.这并非字节顺序的交换. 最佳答案 注意: 以下的算法都用C实现.但应该能够迁移到其他语言(仅仅是不那么快的时候可别找我). 可选方案 内存占用少(32位int.32位机器)(来源于这里) unsigned int reverse(register unsigned int x) { x = (((x & 0xaaaaa…
ylbtech-Java-Class-C:java.util.BigDecimal 1.返回顶部   2.返回顶部   3.返回顶部   4.返回顶部 1. /* * Copyright (c) 1996, 2013, Oracle and/or its affiliates. All rights reserved. * ORACLE PROPRIETARY/CONFIDENTIAL. Use is subject to license terms. * * * * * * * * * * *…
目录 概述 C/C++ 整数的阴暗角落 整型字面量 整型提升与寻常算术转换 算术溢出检测 位运算技巧 总结 参考 概述 无符号数和有符号数是通用的计算机概念,具体到编程语言上则各有各的不同,程序员是解决实际问题的,所以必须熟悉编程语言中的整数.C/C++ 有自己特殊的算术运算规则,如整型提升和寻常算术转换,并且存在大量未定义行为,一不小心就会产生 bug,解决这些 bug 的最好方法就是熟悉整数性质以避免 bug. 我不是语言律师(非贬义),对 C/C++ 算术特性的了解主要来自教材和互联网,但…