Dynamic Rankings Time Limit: 10 Seconds      Memory Limit: 32768 KB The Company Dynamic Rankings has developed a new kind of computer that is no longer satisfied with the query like to simply find the k-th smallest number of the given N numbers. They…

参考链接: http://blog.csdn.net/acm_cxlove/article/details/8565309 http://www.cnblogs.com/Rlemon/archive/2013/05/24/3096264.html http://seter.is-programmer.com/posts/31907.html http://blog.csdn.net/metalseed/article/details/8045038…

Dynamic Rankings Time Limit: 10 Seconds      Memory Limit: 32768 KB The Company Dynamic Rankings has developed a new kind of computer that is no longer satisfied with the query like to simply find the k-th smallest number of the given N numbers. They…

Dynamic Rankings Time Limit: 10 Seconds      Memory Limit: 32768 KB The Company Dynamic Rankings has developed a new kind of computer that is no longer satisfied with the query like to simply find the k-th smallest number of the given N numbers. They…

Distance on the tree DSM(Data Structure Master) once learned about tree when he was preparing for NOIP(National Olympiad in Informatics in Provinces) in Senior High School. So when in Data Structure Class in College, he is always absent-minded about…

Dynamic Rankings Time Limit: 20 Sec Memory Limit: 256 MB 题目连接 http://acm.zju.edu.cn/onlinejudge/showProblem.do?problemCode=2112 Description The Company Dynamic Rankings has developed a new kind of computer that is no longer satisfied with the query l…

POJ 2104为例 思想: 利用归并排序的思想: 建树过程和归并排序类似,每个数列都是子树序列的合并与排序. 查询过程,如果所查询区间完全包含在当前区间中,则直接返回当前区间内小于所求数的元素个数,否则递归的对子树进行求解并相加. 使用STL中的merge对子序列进行合并及排序. 时间复杂度O(nlogn+mlog3n) 代码(vector实现): #include<cstdio> #include<algorithm> #include<vector> #inclu…

Dynamic Rankings Time Limit: 10 Seconds      Memory Limit: 32768 KB The Company Dynamic Rankings has developed a new kind of computer that is no longer satisfied with the query like to simply find the k-th smallest number of the given N numbers. They…

L3-002. 堆栈 时间限制 200 ms 内存限制 65536 kB 代码长度限制 8000 B 判题程序 Standard 作者 陈越 大家都知道“堆栈”是一种“先进后出”的线性结构,基本操作有“入栈”(将新元素插入栈顶)和“出栈”(将栈顶元素的值返回并从堆栈中将其删除).现请你实现一种特殊的堆栈,它多了一种操作叫“查中值”,即返回堆栈中所有元素的中值.对于N个元素,若N是偶数,则中值定义为第N/2个最小元:若N是奇数,则中值定义为第(N+1)/2个最小元. 输入格式: 输入第一行给出正整…

题目链接: http://poj.org/problem?id=2104 K-th Number Time Limit: 20000MSMemory Limit: 65536K 问题描述 You are working for Macrohard company in data structures department. After failing your previous task about key insertion you were asked to write a new data…