An easy problem A Time Limit: 1000/1000MS (Java/Others) Memory Limit: 65535/65535KB (Java/Others) Problem Description N个数排成一列,Q个询问,每次询问一段区间内的数的极差是多少. Input 第一行两个整数N(1≤N≤50000),Q(1≤Q≤200000).接下来一行N个整数a1 a2 a3 -.an,(1≤ai≤1000000000).接下来Q行,每行两个整数L,R(1≤L…
An easy problem B Time Limit: 2000/1000MS (Java/Others) Memory Limit: 65535/65535KB (Java/Others) Problem Description N个数排成一列,每个数的大小为1或者0.有两种操作,第一种操作是把一段区间内的每个数异或1,第二种操作是询问区间内最长连续1的长度. Input 第一行一个整数N(1≤N≤100000),表示N个数.第二行N个数.接下来一行一个整数M(1≤M≤100000),表示…
An easy problem C Time Limit: 4000/2000MS (Java/Others) Memory Limit: 65535/65535KB (Java/Others) Problem Description N个数排成一列,有三种操作.1.给一段区间内的每个数乘上一个非负整数.2.给一段区间内的每个数加上一个非负整数.3.询问一段区间的和模上P的值. Input 第一行两个整数N(1≤N≤100000)表示数的个数,P(1≤P≤1000000000)表示模的值.接下来…
题目119 题目信息 执行结果 本题排行 讨论区 士兵杀敌(三) 时间限制:2000 ms  |  内存限制:65535 KB 难度:5 描写叙述 南将军统率着N个士兵,士兵分别编号为1~N,南将军常常爱拿某一段编号内杀敌数最高的人与杀敌数最低的人进行比較,计算出两个人的杀敌数差值.用这样的方法一方面能鼓励杀敌数高的人,还有一方面也算是批评杀敌数低的人,起到了非常好的效果. 所以,南将军常常问军师小工第i号士兵到第j号士兵中,杀敌数最高的人与杀敌数最低的人之间军功差值是多少. 如今,请你写一个程…
http://acm.hdu.edu.cn/showproblem.php?pid=5475 An easy problem Time Limit: 8000/5000 MS (Java/Others) Memory Limit: 65536/65536 K (Java/Others)Total Submission(s): 755 Accepted Submission(s): 431 Problem Description One day, a useless calculator was…
An easy problem Time Limit: 1 Sec Memory Limit: 256 MB 题目连接 http://acm.hdu.edu.cn/showproblem.php?pid=5475 Description One day, a useless calculator was being built by Kuros. Let's assume that number X is showed on the screen of calculator. At first,…
An easy problem A Time Limit: 2000/1000MS (Java/Others)     Memory Limit: 65535/65535KB (Java/Others) Submit Status N个数排成一列,Q个询问,每次询问一段区间内的数的极差是多少. Input 第一行两个整数N(1≤N≤50000),Q(1≤Q≤200000).接下来一行N个整数a1 a2 a3 ....an,(1≤ai≤1000000000).接下来Q行,每行两个整数L,R(1≤L…
An easy problem Time Limit: 8000/5000 MS (Java/Others)    Memory Limit: 65536/65536 K (Java/Others) Total Submission(s): 467    Accepted Submission(s): 258 Problem Description One day, a useless calculator was being built by Kuros. Let's assume that…
http://acm.hdu.edu.cn/showproblem.php?pid=5475 An easy problem Time Limit: 8000/5000 MS (Java/Others)    Memory Limit: 65536/65536 K (Java/Others)Total Submission(s): 1146    Accepted Submission(s): 560 Problem Description One day, a useless calculat…
An easy problem Time Limit: 8000/5000 MS (Java/Others)    Memory Limit: 65536/65536 K (Java/Others) Problem Description One day, a useless calculator was being built by Kuros. Let's assume that number X is showed on the screen of calculator. At first…
An Easy Problem for Elfness Time Limit: 5000/2500 MS (Java/Others)    Memory Limit: 65535/65535 K (Java/Others)Total Submission(s): 1148    Accepted Submission(s): 234 Problem Description Pfctgeorge is totally a tall rich and handsome guy. He plans t…
An Easy Problem?! Time Limit: 1000MS   Memory Limit: 65536K Total Submissions: 12970   Accepted: 1995 Description It's raining outside. Farmer Johnson's bull Ben wants some rain to water his flowers. Ben nails two wooden boards on the wall of his bar…
A Simple Problem with Integers Time Limit: 10000MS Memory Limit: 65536K Description You have N integers, A1, A2, - , AN. You need to deal with two kinds of operations. One type of operation is to add some given number to each number in a given interv…
题目链接:http://poj.org/problem?id=3468 题解:splay功能比线段树强大当然代价就是有些操作比线段树慢,这题用splay实现的比线段树慢上一倍.线段树用lazy标记差不多要2s用splay要4s.可以用splay来实现线段树的区间操作更深层次的了解一下splay算是入个门. #include <iostream> #include <cstring> #include <cmath> #include <cstdlib> #i…
士兵杀敌(三) 时间限制:2000 ms  |  内存限制:65535 KB 难度:5 描述 南将军统率着N个士兵,士兵分别编号为1~N,南将军经常爱拿某一段编号内杀敌数最高的人与杀敌数最低的人进行比较,计算出两个人的杀敌数差值,用这种方法一方面能鼓舞杀敌数高的人,另一方面也算是批评杀敌数低的人,起到了很好的效果. 所以,南将军经常问军师小工第i号士兵到第j号士兵中,杀敌数最高的人与杀敌数最低的人之间军功差值是多少. 现在,请你写一个程序,帮小工回答南将军每次的询问吧. 注意,南将军可能询问很多…
POJ 2826 An Easy Problem?! -- 思路来自kuangbin博客 下面三种情况比较特殊,特别是第三种 G++怎么交都是WA,同样的代码C++A了 #include <iostream> #include <cstdio> #include <cstring> #include <algorithm> #include <cmath> using namespace std; const double eps = 1e-8;…
An Easy Problem?! Time Limit: 1000MS   Memory Limit: 65536K Total Submissions: 7837   Accepted: 1145 Description It's raining outside. Farmer Johnson's bull Ben wants some rain to water his flowers. Ben nails two wooden boards on the wall of his barn…
含[三点坐标计算面积].[判断两线段是否有交点].[求线段交点]模板   An Easy Problem?! Time Limit: 1000MS   Memory Limit: 65536K Total Submissions:15921   Accepted: 2459 Description It's raining outside. Farmer Johnson's bull Ben wants some rain to water his flowers. Ben nails two…
[HDU4729]An Easy Problem for Elfness 题目大意: 给你一棵\(n(n\le10^5)\)个点的树,树上每条边都有容量. \(m(m\le10^5)\)次询问,每次询问你有\(k\)的预算,可以花\(a\)的代价在任意两点间建一条流容量为\(1\)的边(包括重边),或者花费\(b\)的代价将某条边的容量加\(1\),问在不超过预算的情况下,从\(s\)到\(t\)的最大流量. 思路: 首先,考虑没有\(k,a,b\)的情况,答案就是\(s,t\)路径上的权值最小…
Easy Problem 时间限制:1000 ms  |  内存限制:65536 KB 描写叙述 In this problem, you're to calculate the distance between a point P(xp, yp, zp) and a segment (x1, y1, z1) ? (x2, y2, z2), in a 3D space, i.e. the minimal distance from P to any point Q(xq, yq, zq) on…
Problem E Easy Problem from Rujia Liu? Though Rujia Liu usually sets hard problems for contests (for example, regional contests like Xi'an 2006, Beijing 2007 and Wuhan 2009, or UVa OJ contests like Rujia Liu's Presents 1 and 2), he occasionally sets…
An easy problem Time Limit:3000MS     Memory Limit:32768KB     64bit IO Format:%I64d & %I64u Submit Status Description When Teddy was a child , he was always thinking about some simple math problems ,such as “What it’s 1 cup of water plus 1 pile of d…
Easy Problem from Rujia Liu? Though Rujia Liu usually sets hard problems for contests (for example, regional contests like Xi'an 2006, Beijing 2007 and Wuhan 2009, or UVa OJ contests like Rujia Liu's Presents 1 and 2), he occasionally sets easy probl…
UVa11991 Easy Problem from Rujia Liu?  思路:  构造数组data,使满足data[v][k]为第k个v的下标.因为不是每一个整数都会出现因此用到map,又因为每个数出现次数不等可能相差很大,因此用到vector. 注意:对于数据的清空与判空不要忘记,而map在调用之前必须有map.count的检查. 代码: #include<cstdio> #include<map> #include<vector> using namespac…
Easy Problem from Rujia Liu? Though Rujia Liu usually sets hard problems for contests (for example, regional contests like Xi'an 2006, Beijing 2007 and Wuhan 2009, or UVa OJ contests like Rujia Liu's Presents 1 and 2), he occasionally sets easy probl…
Problem Description We once did a lot of recursional problem . I think some of them is easy for you and some if hard for you. Now there is a very easy problem . I think you can AC it. We can define sum(n) as follow: if i can be divided exactly by 3 s…
An Easy Problem   Description As we known, data stored in the computers is in binary form. The problem we discuss now is about the positive integers and its binary form. Given a positive integer I, you task is to find out an integer J, which is the m…
11991 - Easy Problem from Rujia Liu? Time limit: 1.000 seconds Problem E Easy Problem from Rujia Liu? Though Rujia Liu usually sets hard problems for contests (for example, regional contests like Xi'an 2006, Beijing 2007 and Wuhan 2009, or UVa OJ con…
</pre><h1 style="color: rgb(26, 92, 200);">An easy problem</h1><strong><span style="color: green; font-family: Arial;">Time Limit: 1000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)Tot…
11991 - Easy Problem from Rujia Liu? Though Rujia Liu usually sets hard problems for contests (for example, regional contests likeXi’an 2006, Beijing 2007 and Wuhan 2009, or UVa OJ contests like Rujia Liu’s Presents 1and 2), he occasionally sets easy…