题目链接 http://poj.org/problem?id=1915 题意 输入正方形棋盘的边长.起点和终点的位置,给定棋子的走法,输出最少经过多少步可以从起点走到终点. 思路 经典bfs题目. 代码 #include <iostream> #include <cstdio> #include <cstring> #include <queue> using namespace std; struct Node { int r; int c; int st…

题目链接:https://vjudge.net/problem/POJ-1915 题意:求棋盘上起点到终点最少的步数. 思路:双向广搜模板题,但玄学的是我的代码G++会wa,C++过了,没找到原因QAQ.. AC代码: #include<cstdio> #include<algorithm> #include<queue> using namespace std; ; ][]={-,,-,,,,,,,-,,-,-,-,-,-}; int T,n,sx,sy,ex,ey,…

D - 广搜 基础 Crawling in process... Crawling failed Time Limit:1000MS     Memory Limit:30000KB     64bit IO Format:%I64d & %I64u Submit Status Description BackgroundMr Somurolov, fabulous chess-gamer indeed, asserts that no one else but him can move kni…

Knight Moves Time Limit: 1000MS   Memory Limit: 30000K Total Submissions: 26102   Accepted: 12305 Description Background Mr Somurolov, fabulous chess-gamer indeed, asserts that no one else but him can move knights from one position to another so fast…

Knight Moves Time Limit: 1000MS   Memory Limit: 30000K Total Submissions: 26952   Accepted: 12721 Description Background Mr Somurolov, fabulous chess-gamer indeed, asserts that no one else but him can move knights from one position to another so fast…

#include<iostream> using namespace std; #define SIZE 305 int vis[SIZE][SIZE]; int sx,sy,ex,ey; ]={-,-,-,-,,,,}; ]={-,-,,,,,-,-}; int n,case_num; typedef struct node { int x; int y; int step; }node; node queue[SIZE*SIZE]; void bfs() { int head,tail;…

Knight Moves Time Limit: 1000MS Memory Limit: 30000K Total Submissions: 25909 Accepted: 12244 Description Background Mr Somurolov, fabulous chess-gamer indeed, asserts that no one else but him can move knights from one position to another so fast. Ca…

2243是骑士问题,八个格子的,BFS,因为要最短路经,所以没有用A*,A*跑不出来,太慢了,因为要搜索到所有解啊!一直更新最优,而BFS,一层一层搜索,第一次得到的便是最短的了!300格子,标记的话,BFS遍历所有时间复杂度也算可以!500MS过!稍微剪枝即可!时间注意!要标记每层已经走过的情况时候要在入队的时候标记!大大降低复杂度!因为出队的时候,有些已经在队里了,但是还没有被标记,现在又让他入队! 1915,也是简单BFS过的,暴搜即可.标记一下.但是先用启发搜索怎么也过不了,TLE,用跑…

俩月前写的普通BFS #include <cstdio> #include <iostream> #include <cstring> #include <queue> using namespace std; int CAS,sx,sy,k,ex,ey,vis[305][305],xx[]={1,-1,2,-2,1,-1,2,-2},yy[]={2,-2,1,-1,-2,2,-1,1}; bool check(int x,int y) { return x…

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