475. Heaters Easy Winter is coming! Your first job during the contest is to design a standard heater with fixed warm radius to warm all the houses. Now, you are given positions of houses and heaters on a horizontal line, find out minimum radius of he…

problem 475. Heaters solution1: class Solution { public: int findRadius(vector<int>& houses, vector<int>& heaters){ , cur = , j = ; sort(houses.begin(), houses.end()); sort(heaters.begin(), heaters.end()); ; i<houses.size(); i++) {…

Winter is coming! Your first job during the contest is to design a standard heater with fixed warm radius to warm all the houses. Now, you are given positions of houses and heaters on a horizontal line, find out minimum radius of heaters so that all…

Winter is coming! Your first job during the contest is to design a standard heater with fixed warm radius to warm all the houses. Now, you are given positions of houses and heaters on a horizontal line, find out minimum radius of heaters so that all…

https://leetcode.com/problems/heaters/ 开始的时候,下面的代码对于两边数字完全一样的情况,测试不通过.原因是heater会有重复情况,这时候对于飘红部分就不会往前面继续检查.所以把<改成<=让相同的情况也继续往前面走,走到最后一个,就可以了.Accepted! package com.company; import java.util.Arrays; class Solution { public int findRadius(int[] houses,…

Winter is coming! Your first job during the contest is to design a standard heater with fixed warm radius to warm all the houses. Now, you are given positions of houses and heaters on a horizontal line, find out minimum radius of heaters so that all…

Winter is coming! Your first job during the contest is to design a standard heater with fixed warm radius to warm all the houses. Now, you are given positions of houses and heaters on a horizontal line, find out minimum radius of heaters so that all…

这是悦乐书的第239次更新,第252篇原创 01 看题和准备 今天介绍的是LeetCode算法题中Easy级别的第106题(顺位题号是475).冬天来了!您在比赛期间的第一份工作是设计一个固定温暖半径的标准加热器,以加热所有房屋.现在,您可以在水平线上获得房屋和加热器的位置,找出加热器的最小半径,以便所有房屋都能被这些加热器覆盖.因此,您的输入将分别是房屋和加热器的位置,您的预期输出将是加热器的最小半径.例如: 输入:[1,2,3],[2] 输出:1 说明:唯一的加热器在位置2,如果我们使用半径…

static int wing=[]() { std::ios::sync_with_stdio(false); cin.tie(NULL); ; }(); class Solution { public: int findRadius(vector<int>& houses, vector<int>& heaters) { sort(heaters.begin(),heaters.end()); ; int szHouses=houses.size(); ;i&l…

Winter is coming! Your first job during the contest is to design a standard heater with fixed warm radius to warm all the houses. Now, you are given positions of houses and heaters on a horizontal line, find out minimum radius of heaters so that all…

今日不写日感,直接扔上今日兴趣点: 新研究称火星曾经有一个巨大的地下水系统 链接:https://mbd.baidu.com/newspage/data/landingsuper?context=%7B"nid"%3A"news_6959868648919860397"%7D&n_type=0&p_from=1 ------------------------------------------------题目--------------------…

［抄题］: Winter is coming! Your first job during the contest is to design a standard heater with fixed warm radius to warm all the houses. Now, you are given positions of houses and heaters on a horizontal line, find out minimum radius of heaters so tha…

任意门:http://codeforces.com/contest/1066/problem/B B. Heaters time limit per test 1 second memory limit per test 256 megabytes input standard input output standard output Vova's house is an array consisting of nn elements (yeah, this is the first probl…

http://codeforces.com/contest/1066/problem/B Vova's house is an array consisting of nn elements (yeah, this is the first problem, I think, where someone lives in the array). There are heaters in some positions of the array. The ii-th element of the a…

详见:https://leetcode.com/problems/heaters/description/ C++: class Solution { public: int findRadius(vector<int>& houses, vector<int>& heaters) { int n = heaters.size(), j = 0, res = 0; sort(houses.begin(), houses.end()); sort(heaters.be…

Winter is coming! Your first job during the contest is to design a standard heater with fixed warm radius to warm all the houses. Now, you are given positions of houses and heaters on a horizontal line, find out minimum radius of heaters so that all…

冬季已经来临. 你的任务是设计一个有固定加热半径的供暖器向所有房屋供暖. 现在,给出位于一条水平线上的房屋和供暖器的位置,找到可以覆盖所有房屋的最小加热半径. 所以,你的输入将会是房屋和供暖器的位置.你将输出供暖器的最小加热半径. 说明: 给出的房屋和供暖器的数目是非负数且不会超过 25000. 给出的房屋和供暖器的位置均是非负数且不会超过10^9. 只要房屋位于供暖器的半径内(包括在边缘上),它就可以得到供暖. 所有供暖器都遵循你的半径标准,加热的半径也一样. 示例 1: 输入: [1,2,3…

B. Heaters 这个题目虽然只有1500的分数,但是我还是感觉挺思维的,我今天没有写出来,然后看了一下题解 很少做这种区间覆盖的题目,也不是很擅长,接下来讲讲我看完题解后的思路. 题目大意是:给你一个数列,这个数列的0代表这个地方没有加热器,1代表有,每一个加热器的范围是 [i-r+1,i+r-1] 问你用最少多少个加热器让整个数列都被加热. 我们可以把加热器都放入一个队列,然后用一个数haves来表示[1,haves]的范围已经被覆盖,然后再用一个数now 来表示 根据上一个点 这一个点…

作者: 负雪明烛 id: fuxuemingzhu 个人博客: http://fuxuemingzhu.cn/ 目录 题目描述 题目大意 解题方法 遍历 日期 题目地址:https://leetcode.com/problems/heaters/ 题目描述 Winter is coming! Your first job during the contest is to design a standard heater with fixed warm radius to warm all the…

链接 [http://codeforces.com/contest/1066/problem/B] 分析 具体看代码,贪就完事了 代码 #include<bits/stdc++.h> using namespace std; int main(){ ios::sync_with_stdio(false); cin.tie(0); cout.tie(0); int n,r,k,i,pos; int a[1010]; //freopen("in.txt","r&quo…

题意描述: Vova先生的家可以看作一个n×1的矩形,寒冷的冬天来了,Vova先生想让他的家里变得暖和起来.现在我们给你Vova先生家的平面图,其中111表示这个地方是加热炉,0表示这个地方什么也没有.所有加热器都有一个加热半径r,一个位于ai加热器可以加热[ai−r+1,ai+r−1]的范围.现在,Vova先生想让他的整个家都变得暖和,一开始所有的加热器都是关闭的,请你求出Vova先生最少要开几个加热器才能使整个家变得暖和 输入输出格式: 输入格式: 第一行:两个整数n,r(1≤n,r≤100…

思路: 从左向右贪心选择能覆盖当前位置的最靠右的那个heater即可,和poj radar installation类似. 实现: #include <iostream> #include <cassert> using namespace std; const int INF = 0x3f3f3f3f; ], cov[]; int main() { int n, r; while (cin >> n >> r) { fill(cov + , cov + n…

题意:一个数组只含有0或1,1表示该元素可以覆盖其自身.左边r-1个元素和右边r-1个元素,问最少保留多少个1元素可以覆盖整个数组. 思路:一个指针指向当前未被覆盖的最左边的元素下标,每次找离它最远且能够覆盖它的一个1元素来覆盖,并更新指针. #include<iostream> #include <string.h> #include<cstdio> using namespace std; int main() { int n,r; while(scanf(&quo…

贪心题 策略 在最左边设置一个array 0,每一次从右往左,如果有heater的话就寻找heater左边界是不是小于等于目前的上一个heater的右边界,如果没有一个这样的,那么就直接输出-1 代码(cf的题解的算法) #include <bits/stdc++.h> using namespace std; int a[1100]; main() { int n,r; cin>>n>>r; for(int i=1;i<=n;i++) cin>>a[…

题解:对于每个点 i 来说,从 j = i + r - 1 开始往前找,如果找到一个 a [ j ] 是 1 ,那么就把它选上,但是我们需要判断交界处,也就是如果前面选的那个可以让这个点变温暖,就不用再选多余的了.这样就记录一下前一个 last ,要满足 j > last.找到之后,就更新 i 的值,在 i + k 之间的都可以由选的这个点来温暖. #include <iostream> #include <bits/stdc++.h> using namespace std…

题意:有\(n\)个桩子,\(1\)表示该位置有一个火炉,可以使两边距离为\(r\)的范围照亮,问最少使用多少炉子使得所有范围都被照亮. 题解:贪心,首先我们从\(r\)位置开始向左找,如果找到了就记录这个位置,然后答案+1,然后再从\(2*r-1\)这个位置开始向左找第一个没有标记的火炉,如果没有找到就直接输出\(-1\)结束,否则重复寻找的过程. 代码: int n,r; int a[N]; bool st[N]; int main() { ios::sync_with_stdio(fals…

终于将LeetCode的免费题刷完了,真是漫长的第一遍啊,估计很多题都忘的差不多了,这次开个题目汇总贴,并附上每道题目的解题连接,方便之后查阅吧~ 477 Total Hamming Distance 44.10% Meidum 475 Heaters  30.20% Easy 474 Ones and Zeroes  34.90% Meidum 473 Matchsticks to Square  31.80% Medium 472 Concatenated Words 29.20% Hard…

463. Island Perimeterhttps://leetcode.com/problems/island-perimeter/就是逐一遍历所有的cell,用分离的cell总的的边数减去重叠的边的数目即可.在查找重叠的边的数目的时候有一点小技巧,就是沿着其中两个方向就好,这种题目都有类似的规律,就是可以沿着上三角或者下三角形的方向来做.一刷一次ac,但是还没开始注意codestyle的问题,需要再刷一遍. class Solution { public: int islandPerime…

475. Heaters 思路:每趟循环查找离房子最近的热水器,计算距离,最后取最大距离 public int findRadius(int[] houses, int[] heaters) { Arrays.sort(houses); Arrays.sort(heaters); int j = 0; int res = 0; for(int i = 0; i < houses.length; i++){ //找离house[i]最近的heater while(j < heaters.leng…

Transistor Tutorial Summary Transistor Tutorial Summary Bipolar Junction Transistor Tutorial We can summarise this transistors tutorial section as follows: The Bipolar Junction Transistor (BJT) is a three layer device constructed form two semiconduct…