POJ 1797 Heavy Transportation(Dijkstra)】的更多相关文章

http://poj.org/problem?id=1797 题意 :给出N个城市M条边,每条边都有容量值,求一条运输路线使城市1到N的运输量最大. 思路 :用dijkstra对松弛条件进行变形.解释一下样例吧:从1运到3有两种方案方案1:1-2-3,其中1-2承重为3,2-3承重为5,则可以运送货物的最大重量是3(当大于3时明显1到不了2)方案2:1-3,可知1-3承重为4,故此路可运送货物的最大重量是4,故答案输出4 #include <iostream> #include <std…
F - Heavy Transportation Time Limit:3000MS     Memory Limit:30000KB     64bit IO Format:%I64d & %I64u Submit Status Practice POJ 1797 Description Background Hugo Heavy is happy. After the breakdown of the Cargolifter project he can now expand busines…
Heavy Transportation 题目链接: http://acm.hust.edu.cn/vjudge/contest/66569#problem/A Description Background Hugo Heavy is happy. After the breakdown of the Cargolifter project he can now expand business. But he needs a clever man who tells him whether th…
题目链接: http://poj.org/problem?id=1797 Background Hugo Heavy is happy. After the breakdown of the Cargolifter project he can now expand business. But he needs a clever man who tells him whether there really is a way from the place his customer has buil…
Description Background Hugo Heavy is happy. After the breakdown of the Cargolifter project he can now expand business. But he needs a clever man who tells him whether there really is a way from the place his customer has build his giant steel crane t…
poj 1797 Heavy Transportation Description Background Hugo Heavy is happy. After the breakdown of the Cargolifter project he can now expand business. But he needs a clever man who tells him whether there really is a way from the place his customer has…
传送门 Heavy Transportation Time Limit: 3000MS   Memory Limit: 30000K Total Submissions: 31882   Accepted: 8445 Description Background Hugo Heavy is happy. After the breakdown of the Cargolifter project he can now expand business. But he needs a clever…
Heavy Transportation Time Limit: 3000MS   Memory Limit: 30000K Total Submissions: 26968   Accepted: 7232 Description Background Hugo Heavy is happy. After the breakdown of the Cargolifter project he can now expand business. But he needs a clever man…
Heavy Transportation Time Limit: 3000MS   Memory Limit: 30000K Total Submissions:46898   Accepted: 12204 Description Background Hugo Heavy is happy. After the breakdown of the Cargolifter project he can now expand business. But he needs a clever man…
题意:给你所有道路的载重,找出从1走到n的所有路径中载重最大的,即路径最小值的最大值. 思路:和之前的POJ3268很像.我们用Dijkstra,在每次查找时,我们把最大的先拿出来,因为最大的不影响最小值,然后我们更新的时候,如果当前承重比我们新开辟的路的承重的能力差,那就替换成新的. 注意题目所给数据有重边. 代码: #include<cstdio> #include<set> #include<cmath> #include<stack> #includ…