A. Anastasia and pebbles time limit per test:1 second memory limit per test:256 megabytes input:standard input output:standard output Anastasia loves going for a walk in Central Uzhlyandian Park. But she became uninterested in simple walking, so she…

链接:传送门 题意:这个人每次都去公园捡石子,她有两个口袋,每个口袋最多装 k 个石子,公园有 n 种石子,每种石子 w[i] 个,询问最少几天能将石子全部捡完 思路:排个序,尽量每天都多装,如果 k > w[i] ,那就直接将石子全部放入口袋,如果 k < w[i] 那就多次来装. /************************************************************************* > File Name: Codeforces789A.…

A. Anastasia and pebbles time limit per test 1 second memory limit per test 256 megabytes input standard input output standard output Anastasia loves going for a walk in Central Uzhlyandian Park. But she became uninterested in simple walking, so she…

链接 A. Anastasia and pebbles 题意 这个人有两个口袋,有n种类型的鹅卵石,每种鹅卵石有wi个,每次可以放同一种最多k个,每次不能把不同类型的鹅卵石放进同一个口袋,但是她可以同时把不同种类的鹅卵石放在不同的口袋里,一天只能收集一次,问收集完所有的鹅卵石需要多少天 做法 我们只需要计算出每种类型需要多少次装进袋子里,即 ,然后由于有两个袋子,所以,考虑到不能整除的情况,所以要对结果向上取整,复杂度O(n). 代码 #include<bits/stdc++.h> using…

/* CF789A. Anastasia and pebbles http://codeforces.com/contest/789/problem/A 水题 题意:有两个背包,每次分别可取k个物品,要求每次背包中的物品都是一种 问要取多少次. 对于每种物品,都要取ceil(n/k)次,因此只要加起来再除以2就是答案 */ #include <cstdio> #include <algorithm> #include <cstring> #include <cma…

[题目链接]:http://codeforces.com/contest/789/problem/A [题意] 有n种物品,每种物品有wi个; 你有两个口袋,每个口袋最多装k个物品; 且口袋里面只能装同一种物品; 问你最多需要多少天能拿走所有的物品; 这里你每天只拿一次,也就是说你每天只能使用你的两个口袋一次; 下一天又能使用了; [题解] 贪心即可; 对于每一种物品,如果需要用两个口袋装,就用两个口袋去装; 如果只要一个口袋装,就另外一个口袋装下一种物品 [完整代码] #include <bi…

贪心地一个一个尽可能往口袋里放,容易发现和顺序无关. #include<cstdio> #include<iostream> using namespace std; typedef long long ll; int n,m,a[100100]; ll ans; int main(){ // freopen("a.in","r",stdin); scanf("%d%d",&n,&m); for(int i…

C. CinderellaTime Limit: 20 Sec Memory Limit: 256 MB 题目连接 http://codeforces.com/gym/100685/problem/C Description Cinderella is given a task by her Stepmother before she is allowed to go to the Ball. There are N (1 ≤ N ≤ 1000) bottles with water in th…

题目链接:http://codeforces.com/problemset/problem/459/A 题目大意: 给出两个点(在坐标轴中),求另外两个点从而构成一个正方形,该正方形与坐标轴平行. 如果给的点构不成与坐标轴平行的正方形,则输出 -1. 两点范围: x1, y1, x2, y2 ( - 100 ≤ x1, y1, x2, y2 ≤ 100) .所求两点范围: x3, y3, x4, y4 ( - 1000 ≤ x3, y3, x4, y4 ≤ 1000). 解题思路: 给出两个点,…

题目链接:http://codeforces.com/problemset/problem/710/A 题目大意:在一个棋盘中给出一个位置,判断该位置周围8个点还有几个点可以摆放棋子. AC代码解释解法: #include<bits/stdc++.h> using namespace std; int main() { char c; int x,y; while(~scanf("%c%d",&c,&x)) { getchar(); y=c-; &&…

题目链接: B. Modulo Sum time limit per test 2 seconds memory limit per test 256 megabytes input standard input output standard output You are given a sequence of numbers a1, a2, ..., an, and a number m. Check if it is possible to choose a non-empty subse…

http://acm.hust.edu.cn/vjudge/contest/view.action?cid=102271#problem/B Description Kevin Sun has just finished competing in Codeforces Round #334! The round was 120 minutes long and featured five problems with maximum point values of 500, 1000, 1500,…

A.Beru-taxi 水题:有一个人站在(sx,sy)的位置,有n辆出租车,正向这个人匀速赶来,每个出租车的位置是(xi, yi) 速度是 Vi;求人最少需要等的时间: 单间循环即可: #include<iostream> #include<algorithm> #include<string.h> #include<stdio.h> #include<math.h> #include<vector> using namespace…

这题一眼看就是水题,map随便计 然后我之所以发这个题解,是因为我用了log2()这个函数判断在哪一层 我只能说我真是太傻逼了,这个函数以前听人说有精度问题,还慢,为了图快用的,没想到被坑惨了,以后尽量不用 #include <cstdio> #include <cstdlib> #include <cstring> #include <cmath> #include <iostream> #include <algorithm> #…

题意:给定 n 和 k,然后是 n 个数,表示1-k的一个值,问你修改最少的数,使得所有的1-k的数目都等于n/k. 析:水题,只要用每个数减去n/k,然后取模,加起来除以2,就ok了. 代码如下: #pragma comment(linker, "/STACK:1024000000,1024000000") #include <cstdio> #include <string> #include <cstdlib> #include <cma…

B. Island Time Limit: 1 Sec Memory Limit: 256 MB 题目连接 http://codeforces.com/gym/100114 Description On February 30th this year astronauts from the International Space Station flew over the Pacific Ocean and took a picture, on which was discovered a pr…

Problem G.Giant ScreenTime Limit: 20 Sec Memory Limit: 256 MB 题目连接 http://acm.hust.edu.cn/vjudge/contest/view.action?cid=86821#problem/G Description You are working in Advanced Computer Monitors (ACM), Inc. The company is building and selling giant c…

主题链接:http://codeforces.com/contest/474/problem/B #include <iostream> #include <cmath> #include <algorithm> #include <cstdio> using namespace std; template <class T> inline bool rd(T &ret) { char c; int sgn; if(c=getchar()…

题目链接:https://codeforces.com/contest/1090/problem/A A conglomerate consists of n companies. To make managing easier, their owners have decided to merge all companies into one. By law, it is only possible to merge two companies, so the owners plan to s…

题目链接:http://codeforces.com/problemset/problem/44/E 题意: 给一个字符串,让你分割成 $k$ 行,每行的字母数在 $[a,b]$ 之间. 题解: 这是1500difficulty的DP题? AC代码: #include<bits/stdc++.h> using namespace std; int k,a,b; string s; int main() { cin>>k>>a>>b; cin>>s…

B. s-palindrome 题目连接: http://www.codeforces.com/contest/691/problem/B Description Let's call a string "s-palindrome" if it is symmetric about the middle of the string. For example, the string "oHo" is "s-palindrome", but the…

题意:给定两个相同长度的字符串,让你找出一个字符串,字典序在两都之间. 析:这个题当时WA了好多次,后来才发现是这么水,我们只要把 s 串加上,然后和算数一样,该进位进位,然后再和 t 比较就行. 代码如下: #include <iostream> #include <cstdio> #include <algorithm> #include <vector> #include <set> #include <cstring> #in…

题目链接: A. King Moves 题意: 给出king的位置,问有几个可移动的位置; 思路: 水题,没有思路; AC代码: #include <iostream> #include <cstdio> #include <cstring> #include <algorithm> #include <cmath> #include <bits/stdc++.h> #include <stack> #include &l…

题目链接: A. Round House time limit per test 1 second memory limit per test 256 megabytes input standard input output standard output Vasya lives in a round building, whose entrances are numbered sequentially by integers from 1 to n. Entrance n and entra…

B. BerSU Ball time limit per test 1 second memory limit per test 256 megabytes input standard input output standard output The Berland State University is hosting a ballroom dance in celebration of its 100500-th anniversary! n boys and m girls are al…

原题链接:http://codeforces.com/gym/100431/attachments/download/2421/20092010-winter-petrozavodsk-camp-andrew-stankevich-contest-37-asc-37-en.pdf 题意 神奇的电路可以通过比较器来实现冒泡. 题解 倒着往回考虑,搞搞就好. 代码 #include<iostream> #include<cstdio> #include<cstring> #…

题目链接: A. Maximum Increase time limit per test 1 second memory limit per test 256 megabytes input standard input output standard output You are given array consisting of n integers. Your task is to find the maximum length of an increasing subarray of…

题目链接: A. Pouring Rain time limit per test 1 second memory limit per test 256 megabytes input standard input output standard output A lot of people in Berland hates rain, but you do not. Rain pacifies, puts your thoughts in order. By these years you h…

A. Boy or Girl time limit per test 1 second memory limit per test 256 megabytes input standard input output standard output Description Those days, many boys use beautiful girls' photos as avatars in forums. So it is pretty hard to tell the gender of…

题目链接: http://codeforces.com/contest/659/problem/A 题意: 一个圈,按逆时针编号,给定起点,方向和步数,问终点在几号? 分析: 很简单的模拟...注意答案为0的时候应该输出n... 代码: #include<iostream> using namespace std; int main (void) { int n, a, b;cin>>n>>a>>b; b = (b - 1) %n + 1; int k =…