题目:Reverse Words in a String Given an input string, reverse the string word by word. For example, Given s = "the sky is blue", return "blue is sky the". 比较基础的一个题,拿到这个题,我的第一想法是利用vector来存每一个子串,然后在输出,这是一个比较简单的思路,此外,还有第二个思路,就是对所有的字符反转,然后在针…
Given a string s and a list of strings dict, you need to add a closed pair of bold tag <b> and </b> to wrap the substrings in s that exist in dict. If two such substrings overlap, you need to wrap them together by only one pair of closed bold…
1.单纯的Unicode 转码 String a = "\u53ef\u4ee5\u6ce8\u518c"; a = new String(a.getBytes("UTF-16"),"Unicode"); 2.String 字符串中含有 Unicode 编码时,转为UTF-8 public static String decodeUnicode(String theString) { char aChar; int len = theString…
/** * 方法名称:replaceBlank * 方法描述: 将string字符串中的换行符进行替换为"" * */ public static String replaceBlank(String str) { String dest = ""; if (str != null) { Pattern p = Pattern.compile("\t|\r|\n"); Matcher m = p.matcher(str); dest = m.re…
字符串中单词的逆转,即将单词出现的顺序进行逆转.如将“Today is Friday!”逆转为“Friday! is Today”. #include<iostream> #include<stdio.h> void Reverse(char *pb,char *pe) { if(pb==NULL||pe==NULL) return; while(pb<pe) { char tmp=*pb; *pb=*pe; *pe=tmp; pb++,pe--; } } char *Rev…
//将字符串中的字符逆序输出,但不改变字符串中的内容. #include <stdio.h> /************found************/ void fun (char *a) { if ( *a ) { fun(a+) ;//使用递归进行数组的逆序输出. /************found************/ printf("%c",*a) ; } } void main( ) { ]="abcd"; printf("…
Given two strings s1 and s2, write a function to return true if s2 contains the permutation of s1. In other words, one of the first string's permutations is the substring of the second string. Example 1: Input:s1 = "ab" s2 = "eidbaooo"…
Given two strings s1 and s2, write a function to return true if s2 contains the permutation of s1. In other words, one of the first string's permutations is the substring of the second string. Example 1: Input:s1 = "ab" s2 = "eidbaooo"…
问题 该文章的最新版本已迁移至个人博客[比特飞],单击链接 https://www.byteflying.com/archives/3955 访问. 给定一个字符串,你需要反转字符串中每个单词的字符顺序,同时仍保留空格和单词的初始顺序. 输入: "Let's take LeetCode contest" 输出: "s'teL ekat edoCteeL tsetnoc" 注意:在字符串中,每个单词由单个空格分隔,并且字符串中不会有任何额外的空格. Given a s…
问题 该文章的最新版本已迁移至个人博客[比特飞],单击链接 https://www.byteflying.com/archives/3935 访问. 编写一个函数,以字符串作为输入,反转该字符串中的元音字母. 输入: "hello" 输出: "holle" 输入: "leetcode" 输出: "leotcede" 说明:元音字母不包含字母"y". Write a function that takes a…