leetcode bugfree note】的更多相关文章

463. Island Perimeterhttps://leetcode.com/problems/island-perimeter/就是逐一遍历所有的cell,用分离的cell总的的边数减去重叠的边的数目即可.在查找重叠的边的数目的时候有一点小技巧,就是沿着其中两个方向就好,这种题目都有类似的规律,就是可以沿着上三角或者下三角形的方向来做.一刷一次ac,但是还没开始注意codestyle的问题,需要再刷一遍. class Solution { public: int islandPerime…

Given
 an 
arbitrary
 ransom
 note
 string 
and 
another 
string 
containing 
letters from
 all 
the 
magazines,
 write 
a 
function 
that 
will 
return 
true 
if 
the 
ransom 
 note 
can 
be 
constructed 
from 
the 
magazines ; 
otherwise, 
it 
wil…
public class Solution { public boolean canConstruct(String ransomNote, String magazine) { int[] ransomNum = new int[256]; int[] magNum = new int[256]; for (int i = 0; i < 256; i++) { ransomNum[i] = magNum[i] = 0; } for (int i = 0; i < ransomNote.len…
1. 题目要求 Given a non-empty list of words, return the k most frequent elements. Your answer should be sorted by frequency from highest to lowest. If two words have the same frequency, then the word with the lower alphabetical order comes first. 2. Code…
Discription Given an array of integers, return indices of the two numbers such that they add up to a specific target. You may assume that each input would have exactly one solution, and you may not use the same element twice. Example: Given nums = [2…
LeetCode:Ransom Note [问题再现] Given
 an 
arbitrary
 ransom
 note
 string 
and 
another 
string 
containing 
letters from
 all 
the 
magazines,
 write 
a 
function 
that 
will 
return 
true 
if 
the 
ransom 
 note 
can 
be 
constructed 
from 
the 
magaz…
刷题备忘录,for bug-free leetcode 396. Rotate Function 题意: Given an array of integers A and let n to be its length. Assume Bk to be an array obtained by rotating the array A k positions clock-wise, we define a "rotation function" F on A as follow: F(k…
这是悦乐书的第212次更新,第225篇原创 01 看题和准备 今天介绍的是LeetCode算法题中Easy级别的第80题(顺位题号是383).给定一个任意赎金票据字符串和另一个包含所有杂志字母的字符串,如果赎金票据可以从杂志中构建,则写一个函数将返回true;否则,它将返回false.杂志字符串中的每个字母只能在赎金票据中使用一次.例如: canConstruct("a","b") - > false canConstruct("aa",&…
问题 该文章的最新版本已迁移至个人博客[比特飞],单击链接 https://www.byteflying.com/archives/3937 访问. 给定一个赎金信 (ransom) 字符串和一个杂志(magazine)字符串,判断第一个字符串ransom能不能由第二个字符串magazines里面的字符构成.如果可以构成,返回 true :否则返回 false. (题目说明:为了不暴露赎金信字迹,要从杂志上搜索各个需要的字母,组成单词来表达意思.) 注意:你可以假设两个字符串均只含有小写字母.…
作者: 负雪明烛 id: fuxuemingzhu 个人博客: http://fuxuemingzhu.cn/ 目录 题目描述 题目大意 解题方法 Java解法 Python解法 日期 [LeetCode] 题目地址:https://leetcode.com/problems/ransom-note/ Difficulty: Easy 题目描述 Given an arbitrary ransom note string and another string containing letters…