Piggy-Bank  HDU 1114 初始化的细节问题: 因为要求恰好装满!! 所以初始化要注意: 初始化时除了F[0]为0,其它F[1..V]均设为−∞. 又这个题目是求最小价值: 则就是初始化时除了F[0]为0,其它F[1..V]均设为∞. #include<iostream> #include<stdio.h> #include<algorithm> #include<string.h> using namespace std; const int…

Piggy-Bank Time Limit:1000MS     Memory Limit:32768KB     64bit IO Format:%I64d & %I64u Submit Status Practice HDU 1114 Appoint description:  System Crawler  (2015-09-06) Description Before ACM can do anything, a budget must be prepared and the neces…

Piggy-Bank Time Limit:1000MS     Memory Limit:32768KB     64bit IO Format:%I64d & %I64u Submit Status Practice HDU 1114 Description Before ACM can do anything, a budget must be prepared and the necessary financial support obtained. The main income fo…

HDOJ(HDU).1114 Piggy-Bank (DP 完全背包) 题意分析 裸的完全背包 代码总览 #include <iostream> #include <cstdio> #include <cstring> #include <algorithm> #define nmax 100000 #define INF 0x3f3f3f3f using namespace std; int we[nmax],va[nmax],dp[nmax]; stru…

题目地址:HDU 1114 把dp[0]初始化为0,其它的初始化为INF.这样就能保证最后的结果一定是满的,即一定是从0慢慢的加上来的. 代码例如以下: #include <algorithm> #include <iostream> #include <cstring> #include <cstdlib> #include <cstdio> #include <queue> #include <cmath> #incl…

HDU 1114 Piggy-Bank 完全背包问题. 想想我们01背包是逆序遍历是为了保证什么? 保证每件物品只有两种状态,取或者不取.那么正序遍历呢? 这不就正好满足完全背包的条件了吗 means:给出小猪钱罐的重量和装满钱后的重量,然后是几组数据,每组数据包括每种钱币的价值与重量要求出装满钱罐时的最小价值 #include<cstdio> #include<cstring> #include<cmath> #include<iostream> usin…

题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=1114 简单完全背包,不多说. #include <cstdio> #include <algorithm> #include <cstring> #include <cmath> #include <map> #include <iterator> #include <vector> using namespace std;…

Problem Description Before ACM can do anything, a budget must be prepared and the necessary financial support obtained. The main income for this action comes from Irreversibly Bound Money (IBM). The idea behind is simple. Whenever some ACM member has…

Piggy-Bank Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 42725    Accepted Submission(s): 21075 Problem Description Before ACM can do anything, a budget must be prepared and the necessary fina…

题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=1114 题目大意:根据储钱罐的重量,求出里面钱最少有多少.给定储钱罐的初始重量,装硬币后重量,和每个对应面值硬币的重量. Sample Input 3 10 110 2 1 1 30 50 10 110 2 1 1 50 30 1 6 2 10 3 20 4   Sample Output The minimum amount of money in the piggy-bank is 60. The…