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https://www.hackerrank.com/contests/101hack45/challenges/polynomial-division 询问一个多项式能否整除一个一次函数.a * x + b 注意到如果能整除,就比如是x^2 + 2 * x + 1能整除2 * x + 2 那么它必定能整除2 * x + 2的根,也就是和根肯定有交点. 因为你能整除,也就是(x^2 + 2 * x + 1) = k * (2 * x + 2) 那么k * (2 * x + 2)还是条直线.唯独使…
题目地址: http://acm.fzu.edu.cn/problem.php?pid=1607 给定一个n,将n平均分成m份,问有几种方法,每种方法中找出最大的数.思路:就是求n的因子数.先将每个数求出最小素因子.再将n的所有素因子数加1相乘.小结论:求一个数的所有因子数.先分解.n=(a^x)*(b^y)*(c^z),(a.b.c均为素数),因子数=(x+1)*(y+1)*(z+1)-1. AC代码:输入数据很多,开始用cin果断超时了. #include <iostream> #incl…
作者:王子旭链接:https://zhuanlan.zhihu.com/p/21463650来源:知乎著作权归作者所有.商业转载请联系作者获得授权,非商业转载请注明出处. 2016.7.5 更新:长文多图代码预警,电脑食用效果更佳. 完整版代码已上传 GitHub,后续一些有的没的的代码更新也都在GitHub上(https://github.com/LaytonW/qrcode) 给结尾的几个被自动识别的QR码做了防自动识别..顺便也检测一下我们这不怎么高的容错率(7%).要是再被知乎自动识别了…
Acquired from: ftp.adelaide.edu.au:/pub/rocksoft/crc_v3.txt or ftp://ftp.rocksoft.com/papers/crc_v3.txt or http://www.repairfaq.org/filipg/LINK/F_crc_v3.html A PAINLESS GUIDE TO CRC ERROR DETECTION ALGORITHMS =========================================…
Operations supported for Galois Field arrays: + - - Addition and subtraction of Galois arrays. * / \ - Matrix multiplication and division of Galois arrays. .* ./ .\ - Elementwise multiplication and division of Galois arrays ^ - Matrix exponentiation…
1 Fundamentals A polynomial is either zero, or can be written as the sum of one or more non-zero terms. The number of terms is finite. A term consist of a constant coefficient and a monomial, that is, the product of zero or more variables. Each varia…
https://en.wikipedia.org/wiki/Time_complexity#Polynomial_time An algorithm is said to be of polynomial time if its running time is upper bounded by a polynomial expression in the size of the input for the algorithm, i.e., T(n) = O(nk) for some consta…
(多项式的)因式分解定理(factor theorem)是多项式剩余定理的特殊情况,也就是余项为 0 的情形. 0. 多项式长除法(Polynomial long division) Polynomial long division - Wikipedia 1. 因式分解定理 Factor theorem 该定理表达的是,多项式 f(x) 存在因子 x−k 当且仅当 f(k)=0(余数为 0,也即 k 是其根). 对于多项式 f(x)=x3+7x2+8x+2, x−1 是否为其因子?f(1)≠0…
A. Division time limit per test1 second memory limit per test512 megabytes inputstandard input outputstandard output Oleg's favorite subjects are History and Math, and his favorite branch of mathematics is division. To improve his division skills, Ol…
1.在python2 中导入未来的支持的语言特征中division(精确除法),即from __future__ import division ,当我们在程序中没有导入该特征时,"/"操作符执行的只能是整除,也就是取整数,只有当我们导入division(精确算法)以后,"/"执行的才是精确算法. 如: #python 2.7.6 Python 2.7.6 (default, Nov 10 2013, 19:24:18) [MSC v.1500 32 bit (In…
Equations are given in the format A / B = k, where A and B are variables represented as strings, and k is a real number (floating point number). Given some queries, return the answers. If the answer does not exist, return -1.0. Example:Given a / b =…
Did you ever have the feeling that adding people doesn't help in software development? Did you ever think about the reason? And do you have any idea to make a change? Traditional software engineering emphasizes on division of work by modules, values…
Polynomial Library in OpenCascade eryar@163.com 摘要Abstract:分析幂基曲线即多项式曲线在OpenCascade中的计算方法,以及利用OpenSceneGraph来显示OpenCascade的计算结果,加深对多项式曲线的理解. 关键字Key Words:OpenCascade.PLib.OpenSceneGraph.Polynomial Library 一. 概述 Overview CAGD(Computer Aided Geometry D…
2558: 游起来吧!超妹! Time Limit: 1 Sec  Memory Limit: 128 MBSubmit: 7  Solved: 3[Submit][Status][Web Board] Description 夏天到了,无聊的超妹跑到了落雪湖里抓鱼吃.结果,游到湖的正中 央时被湖边保安看到了,保安要抓住超妹.我们假设落雪湖是一个半径为r的圆形,超妹在圆形的正中心,速度为1.保安由于不会游泳所以只能沿着湖的边缘奔 跑,速度为n.因为超妹在陆地上的速度是很快的,所以我们假设只要超妹…
Contestants Division   Description In the new ACM-ICPC Regional Contest, a special monitoring and submitting system will be set up, and students will be able to compete at their own universities. However there’s one problem. Due to the high cost of t…
刷完了一张代数 P1 计算 $\left( \frac{1}{1}-\frac{1}{2}+\frac{1}{3}-\frac{1}{4}+...+\frac{1}{2011}- \frac{1}{2012}\right) \div \left( \frac{1}{1007}+\frac{1}{1008}+...+frac{1}{2012}\right)$ 这题分隔序列错位相减. 设S1 = 1+1/3+1/5+1/7+1/9+...+1/2011S2 = -1/2-1/4-1/6-1/8-..…
Fruit Ninja II Time Limit: 5000MS Memory limit: 65536K 题目描述 Have you ever played a popular game named "Fruit Ninja"? Fruit Ninja (known as Fruit Ninja HD on the iPad and Fruit Ninja THD for Nvidia Tegra 2 based Android devices) is a video game d…
题目传送门 /* 暴力:对于每一个数都判断,是否数字全都使用过一遍 */ #include <cstdio> #include <iostream> #include <algorithm> #include <cmath> #include <cstring> #include <string> #include <map> #include <set> #include <queue> usin…
GDC2016[全境封锁(Tom Clancy's The Division)]对为何对应Eye Tracked System,以及各种优点的演讲报告 原文 4Gamer編集部:松本隆一 http://www.4gamer.net/games/241/G024173/20160317137/         北美时间2016年3月16日,在旧金山举办的Games Developers Conference 2016上,进行了关于[全境封锁(Tom Clancy's The Division)]的…
Equations are given in the format A / B = k, where A and B are variables represented as strings, and k is a real number (floating point number). Given some queries, return the answers. If the answer does not exist, return -1.0. Example: Given a / b =…
Integration of Polynomial Time Limit: 2000/1000MS (Java/Others) Memory Limit: 128000/64000KB (Java/Others) Submit Statistic Next Problem Problem Description Suppose there are a polynomial which has n nonzero terms, please print the integration polyno…
Description 题目描述 You are given an polynomial of x consisting of only addition marks, multiplication marks, brackets, single digit numbers, and of course the letter x. For example, a valid polynomial would be: (1+x)*(1+x*x+x+5)+1*x*x. You are required…
IMO, version 1 better than version 2, version 2 better than version 3. make some preprocess to make you code simple and efficient. Here divide the input by 2, so you don't have to do dividsion on each loop. version 1 is best thanks to http://www.cnbl…
python解无忧公主数学题107.py """ python解无忧公主数学题107.py http://mp.weixin.qq.com/s?__biz=MzI5ODEwMDQyNw==&mid=402343371&idx=1&sn=0de458a3653a0070ba3912bda7d01db9&scene=25#wechat_redirect 2016年3月9日 12:49:55 codegay """ de…
""" python解无忧公主数学题108回文.py 题目来源: http://mp.weixin.qq.com/s?__biz=MzI5ODEwMDQyNw==&mid=402360973&idx=1&sn=31014f87b8e65c9cd1d40c625c9c3d90&3rd=MzA3MDU4NTYzMw==&scene=6#rd 2016年3月7日 14:59:17 codegay """ #利用到…
圆桌   题意就是每分钟可以将相邻的两个人的位置互换一下 , 问你 ,几分钟可以将所有人的位置互换成    原先的  B 在A的右边 C在A的左边 , 换成现在的 C 在A 的右边 , B 在 A 的 左边 . 看完题目之后就能发现这是一个数学题 , 但是怎么推导方程 呢 ? 我们知道 如果是一条直线想达到这样的效果的话 , n*(n-1)/2 由 冒泡 得之 圆桌的话这样当然是不行的 , 不能直接套上去 . 因为 直线的话 从 第一个 到最后一个 中间是有距离的 , 如果是圆桌的话 没有距离…
Division 紫书入门级别的暴力,可我还是写了好长时间 = = [题目链接]uva 725 [题目类型]化简暴力 &题解: 首先要看懂题意,他的意思也就是0~9都只出现一遍,在这2个5位数中. 接着,你要知道:枚举一个5位数就够了,不用2个5位数都枚举,因为你可以通过n知道第2个5位数. 最后set维护出现的次数,ok判断是否可行,pri输出. [时间复杂度]O(1e5) &代码: #include <bits/stdc++.h> using namespace std;…
题目 解题过程: //物理数学题 #include<stdio.h> #include<string.h> #include<algorithm> using namespace std; int main() { double h,l,v,ans; while(scanf("%lf%lf%lf",&h,&l,&v)!=EOF) { &&l==&&v==)break; ans = h + v *…
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Optimum polynomial If we are presented with the first k terms of a sequence it is impossible to say with certainty the value of the next term, as there are infinitely many polynomial functions that can model the sequence. As an example, let us consid…