只用输入用cin 输出  cout  每个数学符号都可以用   超级强大 #include <iostream> #include <queue> #include <cstdio> #include <cstring> #include <cstdlib> #include <stack> using namespace std; #define maxn 120 class DividedByZeroException {}; c…

Computer Transformation Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 8367    Accepted Submission(s): 3139 Problem Description A sequence consisting of one digit, the number 1 is initially wri…

JAVA 大数开方模板 import java.math.BigInteger; import java.math.*; import java.math.BigInteger; import java.util.Scanner; import java.util.*; public class Main { public static void bigSqrt(){ Scanner cin=new Scanner(System.in); String s=cin.next(); BigInte…

友情提示:使用该模板的注意了,在大数减法里有一个小错误,导致减法可能会出错 // 原来的写法,将t1.len错写成了len ] == && t1.len > ) { t1.len--; big--; } // 改正后 ] == && t1.len > ) { t1.len--; big--; } #include <cstdio> #include <cstring> #include <cstdlib> #include &…

题意:给你一个数n,  定义m=2k-1,   {k|1<=k<=n},并且 k为素数;  当m为合数时,求分解为质因数,输出格式如下:47 * 178481 = 8388607 = ( 2 ^ 23 ) - 1 分析:要分解m,首先要判断m是否为合数,直接用米勒拉宾判断,但是后面的大合数分解,一开始用了试除法,直接给超时.所以,有更加快速的方法.(现学的).使用Pollard_Rho大数分解算法. Pollard_Rho大数分解时间复杂度为n1/4  ac代码: #include <c…

import java.math.BigInteger; import java.util.Scanner; public class Main { public static void main(String[] args) { // TODO Auto-generated method stub Scanner cin=new Scanner(System.in); BigInteger a,b; while(cin.hasNext())//等效于输入到文件尾 { a=cin.nextBig…

Persona5 is a famous video game. In the game, you are going to build relationship with your friends. You have NN friends and each friends have his upper bound of relationship with you. Let's consider the i^{th}ith friend has the upper bound U_iUi​. A…

#include<iostream> #include<cstring> #include<cstdio> #include<iomanip> #include<algorithm> using namespace std; #define MAXN 9999 #define MAXSIZE 10 #define DLEN 4 class BigNum { private: int a[1500]; //可以控制大数的位数 int len; //…

PAT:A1024 Palindromic Number A number that will be the same when it is written forwards or backwards is known as a Palindromic Number. For example, 1234321 is a palindromic number. All single digit numbers are palindromic numbers.Non-palindromic numb…

28-大数阶乘 内存限制:64MB 时间限制:3000ms Special Judge: No accepted:19 submit:39 题目描述: 我们都知道如何计算一个数的阶乘,可是,如果这个数很大呢,我们该如何去计算它并输出它? 输入描述: 输入一个整数m(0<m<=5000) 输出描述: 输出m的阶乘,并在输出结束之后输入一个换行符 样例输入: 复制 50 样例输出: 3041409320171337804361260816606476884437764156896051200000…