hdu4486 Pen Counts(水题)】的更多相关文章

Pen Counts Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others) Total Submission(s): 224    Accepted Submission(s): 127 Problem Description Chicken farmer  Xiaoyan is getting three new chickens, Lucy, Charlie and CC. Sh…
摘自题解: 题意转化一下就是: 给出一列数a[1]...a[n],求长度最长的一段连续的数,使得这些数的和能被M整除. 分析: 设这列数前i项和为s[i], 则一段连续的数的和 a[i]+a[i+1]+...+a[j-1]+a[j]=s[j]-s[i-1], 所以这段连续的数的和能被m整除的条件就是 (s[j]-s[i-1]) % m == 0, 即 s[j]%m-s[i-1]%m == 0, 因此,只需要每一个余数找使s[i]%m等于该余数的最小的i,和s[j]%m等于该余数的最大的j,相减即…
Friendship of Frog Time Limit: 20 Sec Memory Limit: 256 MB 题目连接 http://acm.hdu.edu.cn/showproblem.php?pid=5578 Description N frogs from different countries are standing in a line. Each country is represented by a lowercase letter. The distance betwee…
题目描述: Description Given a specified total t and a list of n integers, find all distinct sums using numbers from the list that add up to t. For example, if t = 4, n = 6, and the list is [4, 3, 2, 2, 1, 1], then there are four different sums that equal…
Pen Counts Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 506    Accepted Submission(s): 319 Problem Description Chicken farmer Xiaoyan is getting three new chickens, Lucy, Charlie and CC. She…
Nasty Hacks Time Limit: 3000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others) Total Submission(s): 3049    Accepted Submission(s): 2364 Problem Description You are the CEO of Nasty Hacks Inc., a company that creates small pieces of…
CSU 1772 漫漫上学路 Time Limit: 1000MS   Memory Limit: 131072KB   64bit IO Format: %lld & %llu Submit Status Description 对于csuxushu来说,能够在CSU(California State University)上学是他一生的荣幸.CSU校园内的道路设计的十分精巧,由n+1条水平道路和n+1条竖直道路等距交错而成,充分体现了校园深厚的文化底蕴.然而不幸的是CS市每到夏季,天降大雨,…
1050: 写一个函数,使给定的一个二维数组(3×3)转置,即行列互换 Time Limit: 1 Sec  Memory Limit: 128 MBSubmit: 154  Solved: 112[Submit][Status][Web Board] Description 写一个函数,使给定的一个二维数组(3×3)转置,即行列互换. Input 一个3x3的矩阵 Output 转置后的矩阵 Sample Input 1 2 3 4 5 6 7 8 9 Sample Output 1 4 7…
DP 水题 Description A number whose only prime factors are 2,3,5 or 7 is called a humble number. The sequence 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 12, 14, 15, 16, 18, 20, 21, 24, 25, 27, ... shows the first 20 humble numbers. Write a program to find and print…
1195: 相信我这是水题 Time Limit: 1 Sec  Memory Limit: 128 MBSubmit: 821  Solved: 219 Description GDUT中有个风云人物pigofzhou,是冰点奇迹队的主代码手,萌萌的师弟师妹们们经常会让pigofzhou帮他们Debug,因为师弟师妹们打代码使用编程语言的种类千奇百怪,pigofzhou为此很头疼.现在假设师弟师妹们只喜欢Java或者C++或者C,因为他希望所有人都学相同的编程语言,只有这样pigofzhou教…