PAT 1081 Rational Sum[分子求和][比较]】的更多相关文章

1081 Rational Sum (20 分) Given N rational numbers in the form numerator/denominator, you are supposed to calculate their sum. Input Specification: Each input file contains one test case. Each case starts with a positive integer N (≤100), followed in…
1081 Rational Sum (20 分)   Given N rational numbers in the form numerator/denominator, you are supposed to calculate their sum. Input Specification: Each input file contains one test case. Each case starts with a positive integer N (≤), followed in t…
题目 Given N rational numbers in the form "numerator/denominator", you are supposed to calculate their sum. Input Specification: Each input file contains one test case. Each case starts with a positive integer N (<=100), followed in the next li…
模拟计算一些分数的和,结果以带分数的形式输出注意一些细节即可 #include <iostream> #include <cstdio> #include <algorithm> #include <cstring> #include <cmath> using namespace std; /* 模拟计算一些分数的和,结果以带分数的形式输出 注意一些细节即可 */ ; ; //long int范围实际上就是int的范围,sqrt(int)不超过…
https://pintia.cn/problem-sets/994805342720868352/problems/994805386161274880 Given N rational numbers in the form "numerator/denominator", you are supposed to calculate their sum. Input Specification: Each input file contains one test case. Eac…
题意: 输入一个正整数N(<=100),接着输入N个由两个整数和一个/组成的分数.输出N个分数的和. AAAAAccepted code: #define HAVE_STRUCT_TIMESPEC #include<bits/stdc++.h> using namespace std; ],b[]; int main(){ ios::sync_with_stdio(false); cin.tie(NULL); cout.tie(NULL); int n; cin>>n; ;i…
简单模拟题. #include<cstdio> #include<cstring> #include<cmath> #include<vector> #include<map> #include<stack> #include<queue> #include<string> #include<algorithm> using namespace std; struct FenShu { long l…
题目如下: Given N rational numbers in the form "numerator/denominator", you are supposed to calculate their sum. Input Specification: Each input file contains one test case. Each case starts with a positive integer N (<=100), followed in the next…
the problem is from PAT,which website is http://pat.zju.edu.cn/contests/pat-a-practise/1081 the code is as followed: #include<stdio.h> #include<math.h> long int gongyue(long int num1, long int num2) { ; if (num1==num2) { gcd = num1; } if (num1…
Given N rational numbers in the form numerator/denominator, you are supposed to calculate their sum. Input Specification: Each input file contains one test case. Each case starts with a positive integer N (≤), followed in the next line N rational num…
1081. Rational Sum (20) 时间限制 400 ms 内存限制 65536 kB 代码长度限制 16000 B 判题程序 Standard 作者 CHEN, Yue Given N rational numbers in the form "numerator/denominator", you are supposed to calculate their sum. Input Specification: Each input file contains one…
Source: PAT A1081 Rational Sum (20 分) Description: Given N rational numbers in the form numerator/denominator, you are supposed to calculate their sum. Input Specification: Each input file contains one test case. Each case starts with a positive inte…
1081. Rational Sum (20) 时间限制 400 ms 内存限制 65536 kB 代码长度限制 16000 B 判题程序 Standard 作者 CHEN, Yue Given N rational numbers in the form "numerator/denominator", you are supposed to calculate their sum. Input Specification: Each input file contains one…
Rational Sum (20) 时间限制 1000 ms 内存限制 65536 KB 代码长度限制 100 KB 判断程序 Standard (来自 小小) 题目描述 Given N rational numbers in the form "numerator/denominator", you are supposed to calculate their sum. 输入描述: Each input file contains one test case. Each case…
Given N rational numbers in the form numerator/denominator, you are supposed to calculate their sum. Input Specification: Each input file contains one test case. Each case starts with a positive integer N (≤), followed in the next line N rational num…
Given N rational numbers in the form "numerator/denominator", you are supposed to calculate their sum. Input Specification: Each input file contains one test case. Each case starts with a positive integer N (<=100), followed in the next line…
1088 Rational Arithmetic(20 分) For two rational numbers, your task is to implement the basic arithmetics, that is, to calculate their sum, difference, product and quotient. Input Specification: Each input file contains one test case, which gives in o…
In mathematics, a rational number is any number that can be expressed in the form of a fraction p/q , where p & q are two integers, and the denominator q is not equal to zero. Hence, all integers are rational numbers where denominator, in the most re…
For two rational numbers, your task is to implement the basic arithmetics, that is, to calculate their sum, difference, product and quotient. Input Specification: Each input file contains one test case, which gives in one line the two rational number…
期望结果:  ID  VAL  CumSum  1  10  10  2  20  30  3  30  60 方法一: 使用分析函数 select id,val,sum(val) over ( order by id ) as CumSum from table 方法二: 如果不支持分析函数,使用join SELECT a.id, sum(b.num) as num from dbo.dt a inner join dbo.dt b on a.id>=b.id group by a.id 参考…
1081 检查密码(15 分) 本题要求你帮助某网站的用户注册模块写一个密码合法性检查的小功能.该网站要求用户设置的密码必须由不少于6个字符组成,并且只能有英文字母.数字和小数点 .,还必须既有字母也有数字. 输入格式: 输入第一行给出一个正整数 N(≤ 100),随后 N 行,每行给出一个用户设置的密码,为不超过 80 个字符的非空字符串,以回车结束. 输出格式: 对每个用户的密码,在一行中输出系统反馈信息,分以下5种: 如果密码合法,输出Your password is wan mei.:…
题目链接: https://leetcode.com/problems/combination-sum/?tab=Description   Problem: 给定数组并且给定一个target,求出所有满足求和等于target的数字组合   遍历所有的数组中元素,然后对target进行更新,将该元素添加到tempList中,直到remain等于0时达到条件,可以将该tempList添加到list中   注意:每个元素可以使用多次,因此每次的遍历都要从上次的那个下标开始.   当target更新到…
1007 Maximum Subsequence Sum (25)(25 分) Given a sequence of K integers { N~1~, N~2~, ..., N~K~ }. A continuous subsequence is defined to be { N~i~, N~i+1~, ..., N~j~ } where 1 <= i <= j <= K. The Maximum Subsequence is the continuous subsequence…
1104. Sum of Number Segments (20) 时间限制 200 ms 内存限制 65536 kB 代码长度限制 16000 B 判题程序 Standard 作者 CAO, Peng Given a sequence of positive numbers, a segment is defined to be a consecutive subsequence. For example, given the sequence {0.1, 0.2, 0.3, 0.4}, we…
题目链接 https://www.patest.cn/contests/pat-a-practise/1104 思路 最容易想到的一个思路就是 遍历一下所有组合 加一遍 但 时间复杂度 太大 会超时 其实可以发现 每个数字的出现频率是有规律的 比如 4 0.1 0.2 0.3 0.4 这组数据 0.1 4 0.2 6 0.3 6 0.4 4 然后 出现次数 刚好满足 (i + 1) * (n - i) 这个公式 AC代码 #include <cstdio> #include <cstri…
本文同步发布在CSDN:https://blog.csdn.net/weixin_44385565/article/details/90486252 1104 Sum of Number Segments (20 分)   Given a sequence of positive numbers, a segment is defined to be a consecutive subsequence. For example, given the sequence { 0.1, 0.2, 0.…
这是在写SQL语句遇到的一个sum  和group bu分组的问题…
Consider a positive integer N written in standard notation with k+1 digits a​i​​ as a​k​​⋯a​1​​a​0​​ with 0 for all i and a​k​​>0. Then N is palindromic if and only if a​i​​=a​k−i​​ for all i. Zero is written 0 and is also palindromic by definition.…
Given a sequence of positive numbers, a segment is defined to be a consecutive subsequence. For example, given the sequence { 0.1, 0.2, 0.3, 0.4 }, we have 10 segments: (0.1) (0.1, 0.2) (0.1, 0.2, 0.3) (0.1, 0.2, 0.3, 0.4) (0.2) (0.2, 0.3) (0.2, 0.3,…
一.我们来查看一个sbook的数据库 二.查看这个表的内容如下 三.表数据如下 四.代码如下 五.结果如下 *&---------------------------------------------------------------------* *& Report Z_TIANPAN_20190717_HELLO *&---------------------------------------------------------------------* *& *…