hdu 6399 City Development

【hdu 6399 City Development】的更多相关文章

hdu 6399 City Development

vjudge 读进来可能会有相同的\(n_i\),不过在相同的\(n_i\)中只有最后一个是有用的,所以其他的要缩起来,缩完后这些\(n\)的数量不会超过19个可以发现一个城市的答案为所有城市初始权值的线性组合,然后对于\(x\),其他和\(x\)gcd深度相同的点转移系数都是一样的,因为gcd深度相同那么转移也是本质相同的那么考虑构造转移矩阵,\(a_{i,j}\)表示gcd深度为\(i\)转移到深度为\(j\)的方案数,那么答案即为\(ans_x=\sum_{i=1}^{n} d_x {…

HDU 1505 City Game （hdu1506 dp二维加强版）

F - City Game Time Limit:1000MS Memory Limit:32768KB 64bit IO Format:%I64d & %I64u Submit Status Practice HDU 1505 Appoint description: Description Bob is a strategy game programming specialist. In his new city building game the gaming enviro…

HDU 3634 City Planning (离散化)

City Planning Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 483 Accepted Submission(s): 203 Problem Description After many years, the buildings in HDU has become very old. It need to rebuil…

hdu 3624 City Planning(暴力，也可扫描线)

City Planning Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others) Total Submission(s): 503 Accepted Submission(s): 213 Problem Description After many years, the buildings in HDU has become very old. It need to rebui…

HDU 5013 City Tour

题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=5013 题意: 思路: 这里有错,是Hi(x)=sigama(Hji)(j属于x) const int N=18; int m,n; double p[N],H[N][N]; double f[N][1<<N]; double dp[N][1<<N]; double a[1<<N],aa[1<<N]; double pp[1<<N],qq[1<&…

HDU 1505 City Game（01矩阵 dp）

Problem Description Bob is a strategy game programming specialist. In his new city building game the gaming environment is as follows: a city is built up by areas, in which there are streets, trees,factories and buildings. There is still some space i…