题目: Given a set of non-overlapping intervals, insert a new interval into the intervals (merge if necessary). You may assume that the intervals were initially sorted according to their start times. Example 1: Given intervals [1,3],[6,9], insert and me…

lc57 Insert Interval 仔细分析题目,发现我们只需要处理那些与插入interval重叠的interval即可,换句话说,那些end早于插入start以及start晚于插入end的interval都可以保留.我们只需要两个指针,i&j分别保存重叠interval中最早start和最晚end即可,然后将interval [i, j]插入即可 class Solution { public int[][] insert(int[][] intervals, int[] newInte…

题目: Given a collection of intervals, merge all overlapping intervals. For example, Given [1,3],[2,6],[8,10],[15,18], return [1,6],[8,10],[15,18]. 题解: 这道题主要难点是改写Comparator. Comparator接口定义了两个方法:compare( )和equals( ).这里给出的compare( )方法按顺序比较了两个元素: int comp…

Given a sorted array and a target value, return the index if the target is found. If not, return the index where it would be if it were inserted in order. You may assume no duplicates in the array. Here are few examples.        [1,3,5,6], 5 → 2      …

Given a set of non-overlapping intervals, insert a new interval into the intervals (merge if necessary). You may assume that the intervals were initially sorted according to their start times. Example 1:Given intervals [1,3],[6,9], insert and merge […

作者:jostree  转载请注明出处 http://www.cnblogs.com/jostree/p/4051169.html 题目链接:leetcode Insert Interval 使用模拟的方法,把需要插入的区间和每一个给定的区间进行比较,有三种情况: 1.给定区间的起点小于要插入区间的终点,并且区间还未被查入过,那么插入区间. 2.给定区间的终点大于要插入区间的起点,或者插入区间已经被插入过了,那么插入给定区间. 3.不满足以上两种情况,说明给定区间与插入区间有交集,那么把需要插入…

Interval的合并时比较常见的一类题目,网上的Amazon面经上也有面试这道题的记录.这里以LeetCode上的例题做练习. Merge Intervals Given a collection of intervals, merge all overlapping intervals. For example,Given [1,3],[2,6],[8,10],[15,18],return [1,6],[8,10],[15,18]. /** * Definition for an inter…

LeetCode中,有很多关于一组interval的问题.大体可分为两类: 1.查看是否有区间重叠: 2.合并重叠区间;  3.插入新的区间: 4. 基于interval的其他问题 [ 做题通用的关键步骤]: 1. 按照begin时间排序: 2. 判断两个相邻区间是否重叠: [假设] a. 给定的区间是半开区间 [begin, end); b. 已经按照"begin"排序. c. 当前的区间是begin, end; 要比较/合并的区间:[ intervals[i][0], interv…

Insert Interval Given a set of non-overlapping intervals, insert a new interval into the intervals (merge if necessary). You may assume that the intervals were initially sorted according to their start times. Example 1:Given intervals [1,3],[6,9], in…

Insert Interval Given a set of non-overlapping intervals, insert a new interval into the intervals (merge if necessary). You may assume that the intervals were initially sorted according to their start times. Example 1:Given intervals [1,3],[6,9], in…