POJ 2289 多重二分匹配+二分 模板】的更多相关文章

The Perfect Stall Time Limit: 1000MS   Memory Limit: 10000K Total Submissions: 23313   Accepted: 10383 Description Farmer John completed his new barn just last week, complete with all the latest milking technology. Unfortunately, due to engineering p…
题意:在通讯录中有N个人,每个人能可能属于多个group,现要将这些人分组m组,设各组中的最大人数为max,求出该最小的最大值 下面用的是朴素的查找,核心代码find_path复杂度是VE的,不过据说可以用DINIC跑二分图可以得到sqrt(v)*E的 #include <iostream> #include <cstdio> #include <cstring> #include <cstdlib> #include <cmath> #incl…
http://poj.org/problem?id=2239 这里要处理的是构图问题p (1 <= p <= 7), q (1 <= q <= 12)分别表示第i门课在一周的第p天的第q节课上 其中二分图的X集合里表示课程i,那么我们要解决的就是Y集合了 将第i门课在一周的第p天的第q节课上进行编号,这样Y集合就是 上课时间的编号了 #include<stdio.h> #include<string.h> #include<math.h> #in…
Description:   You are given a matrix which <= n <= m <= ). You are supposed to choose n elements, there element element in the same column. What is the minimum value of the K_th largest in the n elements you have chosen.   Input:   First line ),…
题目链接:Taxi Taxi Time Limit: 1 Second      Memory Limit: 32768 KB As we all know, it often rains suddenly in Hangzhou during summer time.I suffered a heavy rain when I was walking on the street yesterday, so I decided to take a taxi back school. I foun…
题目:http://acm.zju.edu.cn/onlinejudge/showProblem.do?problemCode=2361 来源:http://acm.hust.edu.cn/vjudge/contest/view.action?cid=26760#problem/B Beloved Sons Time Limit: 2 Seconds      Memory Limit: 65536 KB      Special Judge Once upon a time there liv…
这两道题目都是多重二分匹配+枚举的做法,或者可以用网络流,实际上二分匹配也就实质是网络流,通过枚举区间,然后建立相应的图,判断该区间是否符合要求,并进一步缩小范围,直到求出解.不同之处在对是否满足条件的判断,可以求最大流或者最大匹配看匹配数目是否满足题意. POJ 2289: 多重二分匹配:360ms #include <iostream> #include <cstdio> #include <climits> #include <cstring> #in…
题目链接: Poj 2289 Jamie's Contact Groups 题目描述: 给出n个人的名单和每个人可以被分到的组,问将n个人分到m个组内,并且人数最多的组人数要尽量少,问人数最多的组有多少人? 解题思路: 二分图多重匹配相对于二分匹配来说不再是节点间的一一对应,而是Xi可以对应多个Yi.所以我们就需要一个限制(Xi最多匹配几个Yi).当Yi需要匹配Xi的时候,Xi的匹配未到上限,直接匹配,否则进行增广路.其实是二分图多重匹配的模板题,再套一个二分枚举最多组的人数就OK咯.下面就上板…
POJ 2289(多重匹配+二分) 把n个人,分到m个组中.题目给出每一个人可以被分到的那些组.要求分配完毕后,最大的那一个组的人数最小. 用二分查找来枚举. #include<iostream> #include<string> #include<cstring> #include<cstdio> using namespace std; int map[1010][510]; int vis[1010]; int link[1010][510]; int…
Jamie's Contact Groups Time Limit:7000MS     Memory Limit:65536KB     64bit IO Format:%I64d & %I64u Submit Status Practice POJ 2289 Description Jamie is a very popular girl and has quite a lot of friends, so she always keeps a very long contact list…