Given an integer array, sort it in ascending order. Use quick sort, merge sort, heap sort or any O(nlogn) algorithm.   Example Given [3, 2, 1, 4, 5], return [1, 2, 3, 4, 5]. 快速排序是排序算法中比较重要一种,也是经常容易考的一种排序算法,务必要掌握好.快排的优点是其平均时间复杂度为O(nlgn),这样在给大数据集排序的时候,…

Sort Colors II 原题链接: http://lintcode.com/zh-cn/problem/sort-colors-ii/# Given an array of n objects with k different colors (numbered from 1 to k), sort them so that objects of the same color are adjacent, with the colors in the order 1, 2, ... k. 注意…

Given an integer array, sort it in ascending order. Use selection sort, bubble sort, insertion sort or any O(n2) algorithm.   Example Given [3, 2, 1, 4, 5], return [1, 2, 3, 4, 5]. 这道题让我们实现最基本的几个O(n2)的排序算法,选择排序,冒泡排序和插入排序,都是最基本的排序算法.我们一个一个来看,首先来看冒泡排序,…

Given an unsorted array nums, reorder it such that nums[0] < nums[1] > nums[2] < nums[3].... Notice You may assume all input has valid answer. ExampleGiven nums = [1, 5, 1, 1, 6, 4], one possible answer is [1, 4, 1, 5, 1, 6]. Given nums = [1, 3,…

Given an unsorted array nums, reorder it such that nums[0] < nums[1] > nums[2] < nums[3].... Example 1: Input: nums = [1, 5, 1, 1, 6, 4] Output: One possible answer is [1, 4, 1, 5, 1, 6]. Example 2: Input: nums = [1, 3, 2, 2, 3, 1] Output: One po…

There are a row of n houses, each house can be painted with one of the k colors. The cost of painting each house with a certain color is different. You have to paint all the houses such that no two adjacent houses have the same color. The cost of pai…

Given an array of n objects with k different colors (numbered from 1 to k), sort them so that objects of the same color are adjacent, with the colors in the order 1, 2, ... k. Note You are not suppose to use the library's sort function for this probl…

Given an integer array, sort it in ascending order. Use quick sort, merge sort, heap sort or any O(nlogn) algorithm. 分析 Quick Sort index   0 1 2 3 4 5 6 7 8 9 10 11 12 13 A(key=3)4 1 2 1 5 1 3 2 3 6  2  1  4  3 1       3 1 2 1 5 1 3 2 3 6  2  1  4  4…

原文地址:http://blog.csdn.net/u013074465/article/details/46956295 现在有n个无重复的正整数(n 小于10的7次方),如果内存限制在1.5M以内,要求对着n个数进行排序.[编程珠玑第一章题目] 很显然,10的7次方个整数占用的空间为10 ^ 7 * 4字节,大约等于40M,而内存限制为1.5M,因此,无法将所有数字加载到内存,所以快速排序.堆排序等高效的排序算法就没法使用.这里可以使用bitmap方式,用1bit表示一个整数,那么,10^7…

题目内容: 10个整数排序(别忘了负数) 例如 input 1 0 2 0 3 4 1 9 8 7 output 0 0 1 1 2 3 4 7 8 9 编码: void sort(int *a); int main() { int i,count=0,a[10]; for(i=0; i<10; ++i){ scanf("%d",&a[i]); if(a[i]>=0) count++; } sort(a); return 0; } void sort(int *a)…