题意:c( n, m)%M    M = P1 * P2 * ......* Pk Lucas定理是用来求 c(n,m) mod p,p为素数的值.得出一个存余数数组,在结合中国剩余定理求值 其中有个地方乘积可能超范围,所以按位乘(数论方面薄弱啊,学习学习). #include <iostream> #include <cstdio> #include <cstring> #include <vector> #include <queue> us…

HDU 5446 Unknown Treasure 题意:求C(n, m) %(p[1] * p[2] ··· p[k])     0< n,m < 1018 思路:这题基本上算是模版题了,Lucas定理求C(n,m),再用中国剩余定理合并模方程,因为LL相乘会越界,所以用到按位乘. #include <iostream> #include <cstdio> #include <fstream> #include <algorithm> #inc…

题目链接: http://acm.hdu.edu.cn/showproblem.php?pid=5446 Unknown Treasure 问题描述 On the way to the next secret treasure hiding place, the mathematician discovered a cave unknown to the map. The mathematician entered the cave because it is there. Somewhere…

Unknown Treasure Time Limit: 1500/1000 MS (Java/Others)    Memory Limit: 131072/131072 K (Java/Others)Total Submission(s): 2209    Accepted Submission(s): 821 Problem Description On the way to the next secret treasure hiding place, the mathematician…

题目链接: http://acm.hdu.edu.cn/showproblem.php?pid=5446 题目大意:求C(n, m) % M, 其中M为不同素数的乘积,即M=p1*p2*...*pk, 1≤k≤10.1≤m≤n≤10^18. 分析: 如果M是素数,则可以直接用lucas定理来做,但是M不是素数,而是素数的连乘积.令C(n, m)为 X ,则可以利用lucas定理分别计算出 X%p1,X%p2, ... , X % pk的值,然后用中国剩余定理来组合得到所求结果. 比较坑的地方是,…

Unknown Treasure Time Limit: 1 Sec Memory Limit: 256 MB 题目连接 http://acm.hdu.edu.cn/showproblem.php?pid=5446 Description On the way to the next secret treasure hiding place, the mathematician discovered a cave unknown to the map. The mathematician ent…

Unknown Treasure Time Limit: 1500/1000 MS (Java/Others)    Memory Limit: 131072/131072 K (Java/Others)Total Submission(s): 2389    Accepted Submission(s): 885 Problem Description On the way to the next secret treasure hiding place, the mathematician…

从6点看到10点,硬是没算出来,早知道玩游戏去了,艹,明天继续看 不爽,起来再看,终于算是弄懂了,以后超过一个小时的题不会再看了,不是题目看不懂,是水平不够 #include<cstdio> using namespace std; __int64 result,d; int flag; __int64 gcd(__int64 a,__int64 b,__int64 &x,__int64 &y) { __int64 t,ret; if(!b) { x = ; y = ; ret…

题目链接:Lucky7 题意:求在l和r范围内,满足能被7整除,而且不满足任意一组,x mod p[i] = a[i]的数的个数. 思路:容斥定理+中国剩余定理+快速乘法. (奇+ 偶-) #include <stdio.h> #include <string.h> #include <iostream> using namespace std; #define LL long long #define FOR(i, n) for (int i=0; i<n; +…

Unknown Treasure Time Limit: 1500/1000 MS (Java/Others)    Memory Limit: 131072/131072 K (Java/Others) Problem Description On the way to the next secret treasure hiding place, the mathematician discovered a cave unknown to the map. The mathematician…