题意:对于一个有序数组,输出和为target的两个元素的下标.题目保证仅有唯一解. 分析: 法一:二分.枚举第一个元素,二分找另一个元素,时间复杂度O(nlogn),非最优解. class Solution { public: vector<int> twoSum(vector<int>& numbers, int target) { int len = numbers.size(); vector<int> ans; for(int i = 0; i <…

Two Sum II – Input array is sorted whowhoha@outlook.com Question: Similar to Question [1. Two Sum], except that the input array is already sorted in ascending order. 同上题:先排序,然后从开头和结尾同时向中间查找,原理也比较简单.O(nlogn) runtime, O(1) space vector<int> twoSumSore…

167. Two Sum II - Input array is sorted Given an array of integers that is already sorted in ascending order, find two numbers such that they add up to a specific target number. The function twoSum should return indices of the two numbers such that t…

167. Two Sum II - Input array is sorted[easy] Given an array of integers that is already sorted in ascending order, find two numbers such that they add up to a specific target number. The function twoSum should return indices of the two numbers such…

Given an array of integers that is already sorted in ascending order, find two numbers such that they add up to a specific target number. The function twoSum should return indices of the two numbers such that they add up to the target, where index1 m…

Leetcode之二分法专题-167. 两数之和 II - 输入有序数组(Two Sum II - Input array is sorted) 给定一个已按照升序排列 的有序数组,找到两个数使得它们相加之和等于目标数. 函数应该返回这两个下标值 index1 和 index2,其中 index1 必须小于 index2. 说明: 返回的下标值(index1 和 index2)不是从零开始的. 你可以假设每个输入只对应唯一的答案,而且你不可以重复使用相同的元素. 示例: 输入: numbers…

package y2019.Algorithm.array; /** * @ProjectName: cutter-point * @Package: y2019.Algorithm.array * @ClassName: TwoSum2 * @Author: xiaof * @Description: 167. Two Sum II - Input array is sorted * Given an array of integers that is already sorted in as…

167. Two Sum II - Input array is sorted Easy Given an array of integers that is already sorted in ascending order, find two numbers such that they add up to a specific target number. The function twoSum should return indices of the two numbers such t…

Question 167. Two Sum II - Input array is sorted Solution 题目大意:和Two Sum一样,这里给出的数组是有序的 思路:target - nums[i],这样就实现了降维了 Java实现: public int[] twoSum(int[] nums, int target) { int[] result = new int[2]; Map<Integer, Integer> map = new HashMap<>(); f…

Given an array of integers that is already sorted in ascending order, find two numbers such that they add up to a specific target number. The function twoSum should return indices of the two numbers such that they add up to the target, where index1 m…