Serval and Parenthesis Sequence 题目链接(点击) Serval soon said goodbye to Japari kindergarten, and began his life in Japari Primary School. In his favorite math class, the teacher taught him the following interesting definitions. A parenthesis sequence is…

题目地址:CF1153C Serval and Parenthesis Sequence 思路:贪心 如果有解,那么 \(s_0 = (\) && \(s_{n-1} = )\) && \(n % 2 = 0\) . 如果有解,那么 \(s_1\) ~ \(s_{n-2}\) 为一个合法的括号序列. 那么已知的 \((\) 和 \()\) 个数不能超过一半 接下来贪心:如果有解,那么一定有一组解是把 \(?\) 中左边一部分填成 \((\) ,右边一部分填成 \()\) ,…

冲鸭,去刷题:http://codeforces.com/contest/1153/problem/C C. Serval and Parenthesis Sequence time limit per test 1 second memory limit per test 256 megabytes input standard input output standard output Serval soon said goodbye to Japari kindergarten, and b…

括号正确匹配问题,应该不难 #include <iostream> #include <cstring> #include <string> #include <map> #include <set> #include <algorithm> #include <fstream> #include <cstdio> #include <cmath> #include <stack> #i…

题目链接:http://codeforces.com/contest/1153/problem/C 题意:给定由'(',')','?'组成的字符串,问是否能将其中的?全部换成'(‘,’)'使得字符串的任意非空真字串不构成正确的括号表达式,而整个字符串构成括号表达式,其中正确的括号表达式是指通过插入'1','+'能构成算术式. 思路:我们记'('为-1,')'为1,显然所有字串应满足前面的和<0,字串等于0的话就不满足字串不构成正确的括号表达式了,且整个字符串的和=0(题目可能出现'((((??'…

题目大意:一个字符串只含有? ( ),?可以变成 ) 或者 ( ,将字符串中所有的?变成) 或者 ( 使得字符串合法. 合法就是让括号配对,并且不可以提前结束比如:()()这样是不合法的. 题解:既然不能提前结束,那第一个字符必须和最后一个匹配,所以我们只要关注从2~n-1就可以了. 我们可以正着扫一遍,在任何一个位置")"的数目必须小于等于"("+"?". 然后再倒着扫一遍,同样地,在任何位置的"("的数目必须小于等于&qu…

题目:传送门. 题意:题目说的是求期望,其实翻译过来意思就是:一个长度为 n 的数列(n>=3),按顺序删除其中每一个数,每次删除都是建立在最原始数列的基础上进行的,算出每次操作后得到的新数列的相邻两数的差的绝对值的最大值,求这些n个最大值的总和. 题解:把n=3的情况单独拿出来直接算出来,就是abs(data[3]-data[2])+abs(data[2]-data[1])+abs(data[3]-data[1]),然后讨论n>=4的情况.首先遍历求出原始数列的相邻两数的差的绝对值的最大值m…

题目链接:http://acm.zju.edu.cn/onlinejudge/showProblem.do?problemCode=4060 题意: 给出两个 $0,1$ 字符串 $S,T$,现在你有两次对 $S$ 作区间翻转($0 \rightarrow 1,1 \rightarrow 0$)的操作, 用四元组 $(l_1,r_1,l_2,r_2)$ 表示,代表第一次翻转区间 $[l_1,r_1]$,第二次翻转区间 $[l_2,r_2]$. 问你有多少个四元组可以使得 $S=T$. 题解: 把…

题目链接 题意 : 给出一个排列,让你删除一个数,使得删除后整个序列的 Good 数数量最多.Good 数的定义为 若 Ai 为 Good 则存在 Aj < Ai ( j < i ) 分析 :  画画几个规律就能得出如下几个结论 ① 若删除一个 Good 数,则原序列 Good 数的数量只会减一,即只会影响到这个 Good 数本身 这个也不难证明,若 Ai 是 Good 数,则存在  Aj < Ai ( j < i ) 考虑当前有 Good 数 Ak 因删除 Ai 而变成非 Goo…

题意:给你一串括号,每次仅可以修改一个位置,问有多少位置仅修改一次后所有括号合法. 题解:我们用栈来将这串括号进行匹配,每成功匹配一对就将它们消去,因为题目要求仅修改一处使得所有括号合法,所以栈中最后一定会有两个括号剩余,并且这两个括号要么是\(((\)要么是\())\),\()(\)是无论如何都不合法的,对于\())\),我们去找它左边的\()\)的个数贡献给答案(因为每次修改可以使[\((++\),\()--\)],所以栈中剩余的\())\)就没有了),对于\(((\)的情况也是一样的,我们…

cf-551-div2-D C. Serval and Parenthesis Sequence 题意:给定由'(',')','?'组成的字符串,问是否能将其中的?全部换成'(‘,’)'使得字符串的任意非空真字串不构成正确的括号表达式,而整个字符串构成括号表达式,其中正确的括号表达式是指通过插入'1','+'能构成算术式. 思路:我们记'('为-1,')'为1,显然所有字串应满足前面的和<0,字串等于0的话就不满足字串不构成正确的括号表达式了,且整个字符串的和=0(题目可能出现'((((??'这…

Codeforces Round #551 (Div. 2) 算是放弃颓废决定好好打比赛好好刷题的开始吧 A. Serval and Bus 处理每个巴士最早到站且大于t的时间 #include <bits/stdc++.h> #define fi first #define se second #define pii pair<int,int> #define mp make_pair #define pb push_back #define space putchar(' ')…

A. Serval and Bus 算出每辆车会在什么时候上车, 取min即可 #include<cstdio> #include<algorithm> #include<cstring> #include<queue> #include<iostream> #define ll long long #define M 101 #define mmp make_pair using namespace std; int read() { int…

突然发现上一场没有写,那就补补吧 本来这场应该5题的,结果一念之差E fail了 A. Serval and Bus 基本数学不解释,假如你没有+1 -1真的不好意思见人了 #include<cstdio> #include<iostream> #include<cstring> #include<cstdlib> #include<algorithm> #include<cmath> using namespace std; con…

题目链接:http://codeforces.com/contest/1153 A .Serval and Bus pro:给出n种公交车的首班车时间和两班车之间的时间间隔,找t时间以后的第一辆车是第几种车 sol:对于每种车,找到t时间以后的第一班车的时间,计算这个时间和t的差距,然后找离t最近的 暴力 #include "bits/stdc++.h" using namespace std; ; const int INF = 0x3f3f3f3f; int ans, k = IN…

1809: Parenthesis Submit Page     Summary    Time Limit: 5 Sec     Memory Limit: 128 Mb     Submitted: 1500     Solved: 398 Description Bobo has a balanced parenthesis sequence P=p1 p2…pn of length n and q questions. The i-th question is whether P re…

原题链接 http://acm.csu.edu.cn/OnlineJudge/problem.php?id=1809 Description Bobo has a balanced parenthesis sequence P=p1 p2…pn of length n and q questions. The i-th question is whether P remains balanced after pai and pbi  swapped. Note that questions ar…

1809: Parenthesis Description Bobo has a balanced parenthesis sequence P=p1 p2…pn of length n and q questions. The i-th question is whether P remains balanced after pai and pbi  swapped. Note that questions are individual so that they have no affect…

Problem G: Parenthesis Time Limit: 5 Sec  Memory Limit: 128 MBSubmit: 398  Solved: 75[Submit][Status][Web Board] Description Bobo has a balanced parenthesis sequence P=p1 p2…pn of length n and q questions. The i-th question is whether P remains balan…

Parenthesis Problem Description: Bobo has a balanced parenthesis sequence P=p1 p2-pn of length n and q questions. The i-th question is whether P remains balanced after pai and pbi swapped. Note that questions are individual so that they have no affec…

Bobo has a balanced parenthesis sequence P=p 1 p 2…p n of length n and q questions. The i-th question is whether P remains balanced after p ai and p bi  swapped. Note that questions are individual so that they have no affect on others. Parenthesis se…

题目链接:http://acm.csu.edu.cn/csuoj/problemset/problem?pid=1809 Bobo has a balanced parenthesis sequence P=p 1 p 2…p n of length n and q questions. The i-th question is whether P remains balanced after p ai and p bi  swapped. Note that questions are ind…

1809: Parenthesis Time Limit: 5 Sec     Memory Limit: 128 Mb     Submitted: 2291     Solved: 622 Description Bobo has a balanced parenthesis sequence P=p1 p2…pn of length n and q questions. The i-th question is whether P remains balanced after pai an…

1809: Parenthesis Submit Description Bobo has a balanced parenthesis sequence P=p1 p2…pn of length n and q questions. The i-th question is whether P remains balanced after pai and pbi  swapped. Note that questions are individual so that they have no…

2016湖南省赛----G - Parenthesis (括号匹配)   Bobo has a balanced parenthesis sequence P=p 1 p 2…p n of length n and q questions. The i-th question is whether P remains balanced after p ai and p bi  swapped. Note that questions are individual so that they hav…

Description Bobo has a balanced parenthesis sequence P=p1 p2…pn of length n and q questions. The i-th question is whether P remains balanced after pai and pbi  swapped. Note that questions are individual so that they have no affect on others. Parenth…

  G - Parenthesis Time Limit:5000MS     Memory Limit:131072KB     64bit IO Format:%lld & %llu Description Bobo has a balanced parenthesis sequence P=p 1 p 2-p n of length n and q questions. The i-th question is whether P remains balanced after p ai a…

A.2016 给出正整数 n 和 m,统计满足以下条件的正整数对 (a,b) 的数量: 1. 1≤a≤n,1≤b≤m; 2. a×b 是 2016 的倍数. Input   输入包含不超过 30 组数据. 每组数据包含两个整数 n,m (1≤n,m≤10 9).   Output对于每组数据,输出一个整数表示满足条件的数量.Sample Input 32 63 2016 2016 1000000000 1000000000 Sample Output 1 30576 75231468955026…

A    Live Love 水. #include<bits/stdc++.h> using namespace std; typedef long long ll; ; const int INF = 0x3f3f3f3f; ; ; int n, m; inline void RUN() { int t; scanf("%d", &t); while (t--) { scanf("%d %d", &n, &m); int an…

A Live Love 水 #include <algorithm> #include<cstdio> #include<cstring> using namespace std; typedef long long ll; const int inf = 0x3f3f3f3f; ; int main() { int t; scanf("%d", &t); while(t--) { int n,m; scanf("%d%d"…