UVA11402 - Ahoy, Pirates!(线段树) option=com_onlinejudge&Itemid=8&category=24&page=show_problem&problem=2397" target="_blank" style="">题目链接 题目大意:给你n个01串,每一个串拼接m次得到新串.最后在把这n个新串拼接起来得到终于的目标串. 然后给你四种操作: F a b :把位置a到b都置…
3212: Pku3468 A Simple Problem with Integers Time Limit: 1 Sec Memory Limit: 128 MB Submit: 1278 Solved: 560 [Submit][Status][Discuss] Description You have N integers, A1, A2, - , AN. You need to deal with two kinds of operations. One type of operati…
Minimum Inversion Number Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others) Total Submission(s): 9514 Accepted Submission(s): 5860 Problem Description The inversion number of a given number sequence a1, a2, ..., an…
247-线段树的查询 II 对于一个数组,我们可以对其建立一棵 线段树, 每个结点存储一个额外的值 count 来代表这个结点所指代的数组区间内的元素个数. (数组中并不一定每个位置上都有元素) 实现一个 query 的方法,该方法接受三个参数 root, start 和 end, 分别代表线段树的根节点和需要查询的区间,找到数组中在区间[start, end]内的元素个数. 注意事项 It is much easier to understand this problem if you fin…