On a broken keyboard, some of the keys are always stucked. So when you type some sentences, the characters corresponding to those keys will appear repeatedly on screen for k times. Now given a resulting string on screen, you are supposed to list all…

此文章同步发布在我的CSDN上:https://blog.csdn.net/weixin_44385565/article/details/90041078   1112 Stucked Keyboard (20 分)   On a broken keyboard, some of the keys are always stucked. So when you type some sentences, the characters corresponding to those keys wil…

1112 Stucked Keyboard (20 分) On a broken keyboard, some of the keys are always stucked. So when you type some sentences, the characters corresponding to those keys will appear repeatedly on screen for k times. Now given a resulting string on screen,…

https://pintia.cn/problem-sets/994805342720868352/problems/994805357933608960 On a broken keyboard, some of the keys are always stucked. So when you type some sentences, the characters corresponding to those keys will appear repeatedly on screen for …

题目链接:https://pintia.cn/problem-sets/994805342720868352/problems/994805357933608960 这道题初次写的时候,思路也就是考虑从头到尾遍历一遍,然后如果一个字符重复出现k的倍数次的话,那么这个键就是坏的. 但是这样做交了一发是错的. 后来一想,如果 k = 3,然后出现了aaaba这样一个字符串,那我们并不能仅仅凭a出现了3次就认为a是一个坏键,因为如果它是坏键,那么每一次它在字符串中出现的时候出现的次数都会是k的倍数.…

On a broken keyboard, some of the keys are always stucked. So when you type some sentences, the characters corresponding to those keys will appear repeatedly on screen for k times. Now given a resulting string on screen, you are supposed to list all…

题意: 输入一个正整数K(1<K<=100),接着输入一行字符串由小写字母,数字和下划线组成.如果一个字符它每次出现必定连续出现K个,它可能是坏键,找到坏键按照它们出现的顺序输出(相同坏键仅输出一次,数据保证必定存在坏键),接着输出将坏键修好后原本的字符串(K个连续坏键只输出一次). trick: 测试点1答案错误原因:出现次数为K的倍数而不是大于等于K 测试点2,3错误原因:输出原字符串时没有检验最后一段连续相同字符是否为坏键(循环当中没有检验这一段) AAAAAccepted code:…

题意:给定一个k,键盘里有些键盘卡住了,按一次会打出k次,要求找出可能的坏键,按发现的顺序输出,并且输出正确的字符串顺序. map<char,int>用来标记一个键是否为坏键,一开始的时候都为0,表明所有的键为坏键. 然后遍历每个字符,统计当前字符连续出现的次数cnt,则只要存在cnt%k!=0,则表明为好键,另其map=1. 最后再for一遍字符串,存储坏键字符串和正确字符串,最后输出即可. #include <iostream> #include <cstdio>…

找出一定没问题的字符(即一连串的额字符x个数能被k整除的),剩下的字符都是可能有问题的. #include<cstdio> #include<cstring> #include<cmath> #include<vector> #include<map> #include<queue> #include<stack> #include<algorithm> using namespace std; int k;…

1035 Password (20 分) To prepare for PAT, the judge sometimes has to generate random passwords for the users. The problem is that there are always some confusing passwords since it is hard to distinguish 1 (one) from l (L in lowercase), or 0 (zero) fr…