POJ2689:素数区间筛选】的更多相关文章

Prime Distance Time Limit: 1000MS   Memory Limit: 65536K Total Submissions: 15820   Accepted: 4202 Description The branch of mathematics called number theory is about properties of numbers. One of the areas that has captured the interest of number th…
题目链接: http://poj.org/problem?id=2689 题意: 给出一个区间 [l, r] 求其中相邻的距离最近和最远的素数对 . 其中 1 <= l <  r <= 2,147,483,647, r - l <= 1e6 . 思路: 素数区间筛 要找到 [l, r] 中相邻最近和最远的素数对肯定是需要找出 [l, r] 内所有素数 . 但是无论是直接线性打表还是暴力都处理不了这么大的数据 . 可以先给 sqrt(r) 内的素数打个表, 再用 sqrt(r) 内的…
链接: https://vjudge.net/problem/POJ-2689 题意: The branch of mathematics called number theory is about properties of numbers. One of the areas that has captured the interest of number theoreticians for thousands of years is the question of primality. A…
Problem Description To improve the organization of his farm, Farmer John labels each of his N (1 <= N <= 5,000) cows with a distinct serial number in the range 1..20,000. Unfortunately, he is unaware that the cows interpret some serial numbers as be…
题意:给出一个区间[L,U],找出区间里相邻的距离最近的两个素数和距离最远的两个素数. 用素数筛选法.所有小于U的数,如果是合数,必定是某个因子(2到sqrt(U)间的素数)的倍数.由于sqrt(U)最大也只有2^16,所以我们可以用素数筛选法,先预处理出2~2^16之间的素数,然后再用这些素数筛选出L~U之间的素数.接着就好办了. 有几个要注意的是:1:L为1的情况,可以通过令L=2或者标记isp[0]=false.2:建议用long long,否则很容易在过程中超int范围,导致数组越界RE…
题目链接:http://poj.org/problem?id=2689 题目大意:输入两个数L和U(1<=L<U<=2 147 483 647),要找出两个相邻素数C1和C2(L<=C1<C2<=U)是距离最小的,如果相邻素数不止一对,选择最初的,还要找出两个相邻的素数D1,和D2是距离最大的(同样在有多对的情况下选择最初的) 其中L<U,L和U的差不超过1 000 000 输入样例: 2 1714 17 输出样例: 2,3 are closest, 7,11 a…
Prime Distance Time Limit: 1000MS   Memory Limit: 65536K Total Submissions: 9944   Accepted: 2677 Description The branch of mathematics called number theory is about properties of numbers. One of the areas that has captured the interest of number the…
题目梗概:求1000000以内任意数的最大质因数是第几个素数,其中 定义 1为第0个,2为第1个,以此类推. #include<string.h> #include<stdio.h> #include<math.h> ],b[],c[];//b[i]表示i是第几个素数,c[k]表示k的最大素数是c[k],a[i]表示是不是素数 int main() { int n,i,num,j; memset(a,,sizeof(a)); a[]=; b[]=; num=; ;i&l…
Problem Description Give you a lot of positive integers, just to find out how many prime numbers there are. Input There are a lot of cases. In each case, there is an integer N representing the number of integers to find. Each integer won't exceed 32-…
Description Diophantus of Alexandria was an egypt mathematician living in Alexandria. He was one of the first mathematicians to study equations where variables were restricted to integral values. In honor of him, these equations are commonly called d…