problem: Given an input string, reverse the string word by word. For example: Given s = "the sky is blue", return "blue is sky the". 问题分析:如何准确的找到每一个需要清除的空格的位置pos,以及每个word对应的pos范围? 解决方法:需要反转一个字符串,使用int string.find_last_not_of(char c, in…
Given an input string, reverse the string word by word. For example, Given s = "the sky is blue", return "blue is sky the". click to show clarification. Clarification: What constitutes a word? A sequence of non-space characters constit…
题目:Given an input string, reverse the string word by word. For example,Given s = "the sky is blue",return "blue is sky the". 要求: 1)首尾有空格的时候,反转后的string要将空格去掉 2)当string有多个连续空格的时候,只保留一个空格. 代码分析: 对多余空格剔除: 思路分析: 1)从原始s 的最末尾开始扫描,如果遇到空格,用whil…
Given an input string, reverse the string word by word. For example,Given s = "the sky is blue",return "blue is sky the". Update (2015-02-12):For C programmers: Try to solve it in-place in O(1) space. click to show clarification. Clari…
#include <iostream> #include <string> #include <algorithm> #include <cstring> inline void STL_Reverse(std::string& str) // 反转string字符串 包装STL的reverse() 可以inline { reverse(str.begin(), str.end()); // STL 反转函数 reverse() 的实现 /* tem…
作者: 负雪明烛 id: fuxuemingzhu 个人博客: http://fuxuemingzhu.cn/ 目录 题目描述 题目大意 解题方法 栈 日期 题目地址:https://leetcode.com/problems/remove-all-adjacent-duplicates-in-string/ 题目描述 Given a string S of lowercase letters, a duplicate removal consists of choosing two adjac…
今天又遇见了这个该死的问题,还是记下来备忘. 从map里取值的时候,将OBJECT对象 先转换成String 然后转换成integer报错 java.lang.NumberFormatException: For input string: "[Ljava.lang.String;@1352dda" at java.lang.NumberFormatException.forInputString(NumberFormatException.java:48) at java.lang.…
Convert List, string. A List can be converted to a string. This is possible with the ToArray method on the List type. We can also convert a string into a List.ConversionsThe StringBuilder type helps with certain conversions, which are done with loops…
https://leetcode.com/problems/word-break/ Given a string s and a dictionary of words dict, determine if s can be segmented into a space-separated sequence of one or more dictionary words. For example, givens = "leetcode",dict = ["leet"…
https://leetcode.com/problems/word-search/ class Solution { public: struct Trie{ Trie *next[]; bool isWord; Trie() { this->isWord = false; for(auto &c: next) c = NULL; } }; void insert(Trie *root, string word) { Trie *p = root; for(auto &c: wor…