Long Long Message 后缀数组入门题】的更多相关文章

Long Long Message Time Limit: 4000MS   Memory Limit: 131072K Total Submissions: 22564   Accepted: 9255 Case Time Limit: 1000MS Description The little cat is majoring in physics in the capital of Byterland. A piece of sad news comes to him these days:…
题意 给定字符串A.B,求其最长公共子串 后缀数组模板题,求出height数组,判断sa[i]与sa[i-1]是否分属字符串A.B,统计答案即可. #include <cstdio> #include <cstdlib> #include <cstring> #include <string> #include <algorithm> #include <iostream> using namespace std; ; char st…
Time Limit: 4000MS   Memory Limit: 131072K Total Submissions: 24756   Accepted: 10130 Case Time Limit: 1000MS Description The little cat is majoring in physics in the capital of Byterland. A piece of sad news comes to him these days: his mother is ge…
BZOJ 1031 [JSOI2007]字符加密Cipher | 后缀数组模板题 将字符串复制一遍接在原串后面,然后后缀排序即可. #include <cmath> #include <cstdio> #include <cstring> #include <algorithm> #define space putchar(' ') #define enter putchar('\n') using namespace std; typedef long l…
前言 看这篇博客前,先去了解一下后缀数组的基本操作吧:后缀数组入门(一)--后缀排序. 这篇博客的内容,主要建立于后缀排序的基础之上,进一步研究一个\(Height\)数组以及如何求\(LCP\). 什么是\(LCP\) \(LCP\),即\(Longest\ Common\ Prefix\),是最长公共前缀的意思. 而在后缀数组中,\(LCP(i,j)\)表示后缀\(_{SA_i}\)与后缀\(_{SA_j}\)的最长公共前缀的长度,注意是\(SA_i\)和\(SA_j\),而不是\(i\)和…
Language: Default Long Long Message Time Limit: 4000MS   Memory Limit: 131072K Total Submissions: 21228   Accepted: 8708 Case Time Limit: 1000MS Description The little cat is majoring in physics in the capital of Byterland. A piece of sad news comes…
后缀数组: #include<cstdio> #include<algorithm> #include<cstring> #include<vector> using namespace std; typedef long long ll; ,mod=; char s[N]; ],Log[N]; void Sort(int* x,int* y,int m) { ; i<m; ++i)c[i]=; ; i<n; ++i)++c[x[i]]; ; i…
题目链接 http://acm.hdu.edu.cn/showproblem.php?pid=5558 Problem Description Alice wants to send a classified message to Bob. She tries to encrypt the message with her original encryption method. The message is a string S, which consists of Nlowercase let…
Long Long Message   Description The little cat is majoring in physics in the capital of Byterland. A piece of sad news comes to him these days: his mother is getting ill. Being worried about spending so much on railway tickets (Byterland is such a bi…
题意: 求两个字符串的LCP SOL: 模板题.连一起搞一搞就好了...主要是记录一下做(sha)题(bi)过程心(cao)得(dan)体(xin)会(qing) 后缀数组概念...还算是简单的,过程也非常清晰...就是老人家...马丹代码那么写意真的是...每一句代码的意思大概都知道但是不能很准确的描述...自己实现又漏洞百出...所以虽然避免了抄模板...但还是相当于一个默写的过程... 然后这个题目...非常显然嘛不是...然后就打了...然后开始调...TLE...TLE...TLE..…