Installing on RPM-based Linux (RHEL, CentOS, Fedora, openSUSE) — RabbitMQ https://www.rabbitmq.com/install-rpm.html ulimit -n 1024 Controlling System Limits on Linux RabbitMQ installations running production workloads may need system limits and kerne…
#include <stdio.h> #include <sys/types.h> #include <fcntl.h> #include <stdlib.h> #include <unistd.h> int main(int argc,char *argv[]){ int fd; ]; ; ){ sprintf(name,"file%d",++i); fd = open(name,O_CREAT,); //超过最大打开数时再…
Jeff Janes: Hi, As part of our monitoring work for our customers, we stumbled upon an issue with our customers' servers who have a wal_keep_segments setting higher than 0. We have a monitoring script that checks the number of WAL files in the pg_xlog…
  Guillaume Lelarge: Hi, As part of our monitoring work for our customers, we stumbled upon an issue with our customers' servers who have a wal_keep_segments setting higher than 0. We have a monitoring script that checks the number of WAL files in th…
How do I increase the maximum number of open files under CentOS Linux? How do I open more file descriptors under Linux? The ulimit command provides control over the resources available to the shell and/or to processes started by it, on systems that a…
现象:测试服务是去redis循环取数据,早上发现服务挂了,手动登陆redis 无法输入命令,报错:max number of clients reached Redis…
InnoDB: The log sequence number in ibdata files does not matchInnoDB的:在ibdata文件的日志序列号不匹配 可能ibdata文件损坏了解决办法如下:在my.cny 的[mysqld]中加入 # Size of each log file in a log group. You should set the combined size      # of log files to about 25%-100% of your b…
早上发现微服务连不上redis cluster了,看来下日志如下 [root@win-jrh378d7scu 7005]# bin/redis-cli -c -h 15.31.213.183 -p 700515.31.213.183:7005> cluster infoERR max number of clients reached15.31.213.183:7005> 2019-03-26 22:00:30.011 http-nio-9090-exec-4 ERROR org.apache…
查看redis监控的时候看到redis的graph出现不正常的情况,截图如下: 如上面截图所展示的样子,可以看到redis 的客户端连接数很突兀的上升到10K,又突然下降到0.排除了监控本身的原因,很明显是因为redis本身出了问题. 进入redis服务器,连接上去 /usr/bin/redis-cli -p 6399 -h 127.0.0.1 >127.0.0.1:6399>> info ERR max number of clients reached 无论执行命令,显示的都是上面的…
leetcode 321 Create Max Number greedy的方法,由于有两个数组,我们很自然的想到从数组1中选i个数,数组2中选k-i个数,这样我们只需要遍历max(0, k-数组2长度n) ~ 数组1长度,然后保存合并i和k-i这两个部分之后得到的最大值即可. 那么还剩下这几个问题: 1) 从一个数组中不改变元素顺序地选出i个元素,使他们顺序排列代表的十进制数最大.例:[1,4,3,6,2], i = 3, 结果为[4,6,2] 2) 如何合并数组1的i个元素和数组2的k-i个…