Binary Search模板: mid 和 target 指针比较,left/ right 和 target 比较. 循环终止条件: 最后剩两数比较(while(left + 1 < right)). 循环结束后根据要求检查最后两个数(left/ right 和 target 比较). public class Solution { /** *@param A : an integer sorted array *@param target : an integer to be inserte…

Given a binary search tree and a new tree node, insert the node into the tree. You should keep the tree still be a valid binary search tree. Example Given binary search tree as follow: 2 / \ 1 4 / 3 after Insert node 6, the tree should be: 2 / \ 1 4…

Binary search is a famous question in algorithm. For a given sorted array (ascending order) and a target number, find the first index of this number in O(log n) time complexity. If the target number does not exist in the array, return -1. Example If…

Closest Binary Search Tree Value  Given a non-empty binary search tree and a target value, find the value in the BST that is closest to the target. Note: Given target value is a floating point. You are guaranteed to have only one unique value in the…

Given a sorted array and a target value, return the index if the target is found. If not, return the index where it would be if it were inserted in order. You may assume no duplicates in the array. Example 1: Input: [1,3,5,6], 5 Output: 2 Example 2:…

二叉搜索树是常用的概念,它的定义如下: The left subtree of a node contains only nodes with keys less than the node's key. The right subtree of a node contains only nodes with keys greater than the node's key. Both the left and right subtrees must also be binary search…

题目 不同的二叉查找树 给出 n,问由 1...n 为节点组成的不同的二叉查找树有多少种? 样例 给出n = 3,有5种不同形态的二叉查找树: 1 3 3 2 1 \ / / / \ \ 3 2 1 1 3 2 / / \ \ 2 1 2 3 解题 public class Solution { /** * @paramn n: An integer * @return: An integer */ public int numTrees(int n) { // write your code…

C++ /** * Definition of TreeNode: * class TreeNode { * public: * int val; * TreeNode *left, *right; * TreeNode(int val) { * this->val = val; * this->left = this->right = NULL; * } * } */ class Solution { public: /** * @param A: A sorted (increasi…

Binary Search T(n) = T(n/2) + O(1)   =>    T(n) = O(lg n) proof: 如果能用iterable , 就用while loop, 可以防止用recursion的时候stack overflow( process in Linux is 8Mb), stack room is static for each process. (堆空间, heap room 是内存, 是动态的.)层数越多,存储更多中间/临时变量,最终超过系统配的stack空…

A binary search tree is provided for efficiently organizing values for a set of items, even when values are duplicated. In generating the binary search tree, the value of each item in a set of values is determined. If a particular value is unique and…