Maya Calendar Time Limit: 1000MS Memory Limit: 10000K Total Submissions: 82431 Accepted: 25319 Description During his last sabbatical, professor M. A. Ya made a surprising discovery about the old Maya calendar. From an old knotted message, professor…

Maya Calendar Time Limit: 1000MS   Memory Limit: 10000K Total Submissions: 64795   Accepted: 19978 Description During his last sabbatical, professor M. A. Ya made a surprising discovery about the old Maya calendar. From an old knotted message, profes…

链接:http://poj.org/problem?id=1008 Maya Calendar Time Limit: 1000MS   Memory Limit: 10000K Total Submissions: 71745   Accepted: 22083 Description During his last sabbatical, professor M. A. Ya made a surprising discovery about the old Maya calendar. F…

    Maya Calendar Time Limit: 1000MS   Memory Limit: 10000K Total Submissions: 62297   Accepted: 19221 Description During his last sabbatical, professor M. A. Ya made a surprising discovery about the old Maya calendar. From an old knotted message, pr…

一. 题目 Maya Calendar Time Limit: 1000MS   Memory Limit: 10000K Total Submissions: 74085   Accepted: 22819 Description During his last sabbatical, professor M. A. Ya made a surprising discovery about the old Maya calendar. From an old knotted message,…

1.Link: http://poj.org/problem?id=1008 http://bailian.openjudge.cn/practice/1008/ 2.content: Maya Calendar Time Limit: 1000MS   Memory Limit: 10000K Total Submissions: 66971   Accepted: 20644 Description During his last sabbatical, professor M. A. Ya…

题目:http://poj.org/problem?id=3393 不多说了,简单模拟题,因为粗心写错了两个字母,导致错了N遍,模拟还是一贯的恶心,代码实在不想优化了,写的难看了点.. #include <stdio.h> #include <string.h> ; ; ] = {, , , , , , , , , , , , }; ][]; ][][]; int main() { ; i <= ; i++) { memcpy(days[i], month, sizeof(m…

Crossword Answers Time Limit: 1000MS   Memory Limit: 30000K Total Submissions: 869   Accepted: 405 Description A crossword puzzle consists of a rectangular grid of black and white squares and two lists of definitions (or descriptions). One list of de…

问题描述: 宇航员在太空中迷失了方向,在他的起始位置现在建立一个虚拟xyz坐标系,称为绝对坐标系,宇航员正面的方向为x轴正方向,头顶方向为z轴正方向,则宇航员的初始状态如下图所示: 现对六个方向分别标号,x,y,z正方向分别为0,1,2,负方向分别为3,4,5:称它们为绝对方向.宇航员在宇宙中只沿着与绝对坐标系xyz轴平行的方向行走,但是他不知道自己当前绝对坐标和自己面向的绝对方向. 任务描述: 请根据宇航员对自己在相对方向上移动的描述确定宇航员最终的绝对坐标和面向的绝对方向.对在相对方向上移动…

参考:https://blog.csdn.net/u011392408/article/details/28866779 https://blog.csdn.net/qq_36424540/article/details/78234240 #include <iostream> #include <cstdio> #include <cstring> using namespace std; int d,y; string s; //string sh[]={"…