POJ2688状态压缩(可以+DFS剪枝)】的更多相关文章

题意:       给你一个n*m的格子,然后给你一个起点,让你遍历所有的垃圾,就是终点不唯一,问你最小路径是多少? 思路:       水题,方法比较多,最省事的就是直接就一个BFS状态压缩暴搜就行了,时间复杂度20*20*1024的,完全可以接受,但是被坑了,一开始怎么交都TLE,后来又写了一个BFS+DFS优化,就是跑之前先遍历一遍图,看看是不是所有的垃圾点都能遍历到,这样还是超时,无奈看了下讨论,有人说用G++交就行了,我用G++交了结果两个方法都AC了,哎!下面是两个方法的代码,比较简…
Description Flip game squares. One side of each piece is white and the other one is black and each piece is lying either it's black or white side up. Each round you flip 3 to 5 pieces, thus changing the color of their upper side from black to white a…
题意:给出n个点,以及m条边,这些边代表着这些点相连,修一个电力站,若在某一点修一个站,那么与这个点相连的点都可以通电,问所有的点都通电的话至少要修多少个电力站........ 思路:最多给出的是35个点,那么若是搜索的话,就是2^35......考虑状态压缩剪枝,若某个点修电力站,那么周围的所有点都有电了.... #include<iostream> #include<stdio.h> #include<string.h> using namespace std; t…
[题目描述] In the game of Sudoku, you are given a large 9 × 9 grid divided into smaller 3 × 3 subgrids. For example, . 2 7 3 8 . . 1 . . 1 . . . 6 7 3 5 . . . . . . . 2 9 3 . 5 6 9 2 . 8 . . . . . . . . . . . 6 . 1 7 4 5 . 3 6 4 . . . . . . . 9 5 1 8 . .…
B. Preparing Olympiad You have n problems. You have estimated the difficulty of the i-th one as integer ci. Now you want to prepare a problemset for a contest, using some of the problems you've made. A problemset for the contest must consist of at le…
最大联通子数组,这次的题目,我采用的方法为dfs搜索,按照已经取到的数v[][],来进行搜索过程的状态转移,每次对v[][]中标记为1的所有元素依次取其相邻的未被标记为1的元素,将其标记为1,然而,这样会产生很大的子问题重合,所以必须利用dp来进行记忆化搜索,dp为一集合,集合中的元素为已在前面出现过的v[][]的状态, 然而v[][]为一个二维数组,很不方便存入set,所以使用将v[][]的行经行状态压缩,使用位运算,将行存入 long long 型数中,在按列存入vector中 #inclu…
UVA 1508 - Equipment 状态压缩 枚举子集 dfs ACM 题目地址:option=com_onlinejudge&Itemid=8&category=457&page=show_problem&problem=4254" target="_blank" style="color:rgb(0,136,204); text-decoration:none">UVA 1508 - Equipment--P…
题目链接:https://hihocoder.com/problemset/problem/1334 时间限制:10000ms 单点时限:1000ms 内存限制:256MB 描述 Given N words from the top 100 common words in English (see below for reference), select as many words as possible as long as no two words share common letters.…
比赛链接:http://codeforces.com/problemset/problem/550/B 给你n个数,选出来只是2个然后求他们的和在L和R的区间内,并且选出来的数中最大值和最小值的差不得小于x,求共有多少种选法 下面是dfs搜出来的; #include<cstdio> #include<iostream> #include<algorithm> #include<cstring> #include<cmath> #define me…
Hie with the Pie Time Limit: 2000MS   Memory Limit: 65536K Total Submissions: 6436   Accepted: 3470 Description The Pizazz Pizzeria prides itself in delivering pizzas to its customers as fast as possible. Unfortunately, due to cutbacks, they can affo…