B. Amr and The Large Array time limit per test 1 second memory limit per test 256 megabytes input standard input output standard output Amr has got a large array of size n. Amr doesn't like large arrays so he intends to make it smaller. Amr doesn't c…

题目链接:http://codeforces.com/problemset/problem/558/B 题目意思:给出一个序列,然后找出出现次数最多,但区间占用长度最短的区间左右值. 由于是边读入边比较,因此问题最关键的是,记录每个数第一次出现的位置,即左值.因为要保证次数是出现最多,因此需要一个cnt[]数组来记录出现次数.然后当最多出现次数与当前cnt[x]次数相同时,要选择区间较短的,再更新左右区间值. 赛中短路竟然想不出来~~~泪啊~~泪啊- >_< #include <iost…

题意:有一个数组.如今要削减它的尺寸.数组中同样元素的个数的最大值为数组的魅力值,要求削减后魅力值不能降低,同一时候要尽可能的把尺寸减到最小 分析:水题,主要是不要想复杂了.还有就是沉下心来做 代码: #include<iostream> #include<cstring> #include<algorithm> #define INF 1000000007 #define max(a,b) a>b?a:b using namespace std; int n,a…

题目链接: B. Amr and The Large Array time limit per test 1 second memory limit per test 256 megabytes input standard input output standard output   Amr has got a large array of size n. Amr doesn't like large arrays so he intends to make it smaller. Amr d…

B. Amr and The Large Array Time Limit: 20 Sec Memory Limit: 256 MB 题目连接 http://codeforces.com/contest/558/problem/B Description Amr has got a large array of size n. Amr doesn't like large arrays so he intends to make it smaller. Amr doesn't care abou…

B. Amr and The Large Array time limit per test 1 second memory limit per test 256 megabytes input standard input output standard output Amr has got a large array of size n. Amr doesn't like large arrays so he intends to make it smaller. Amr doesn't c…

B. Amr and The Large Array time limit per test 1 second memory limit per test 256 megabytes input standard input output standard output Amr has got a large array of size n. Amr doesn't like large arrays so he intends to make it smaller. Amr doesn't c…

time limit per test1 second memory limit per test256 megabytes inputstandard input outputstandard output Amr has got a large array of size n. Amr doesn't like large arrays so he intends to make it smaller. Amr doesn't care about anything in the array…

Amr has got a large array of size n. Amr doesn't like large arrays so he intends to make it smaller. Amr doesn't care about anything in the array except the beauty of it. The beauty of the array is defined to be the maximum number of times that some…

Description Amr has got a large array of size n. Amr doesn't like large arrays so he intends to make it smaller. Amr doesn't care about anything in the array except the beauty of it. The beauty of the array is defined to be the maximum number of time…

二次联通门 : Codeforces 221d D. Little Elephant and Array /* Codeforces 221d D. Little Elephant and Array 题意 : 询问一段区间中出现次数等于自身的数的个数 正解是dp 莫队水过, 作为我莫队的入门题 myj的思路 66 把所有需查询的区间排序 当前查询区间的答案为上一个区间的答案通过多次的区间移动得出 */ #include <algorithm> #include <cstdio>…

C. Amr and Chemistry Problem's Link: http://codeforces.com/problemset/problem/558/C Mean: 给出n个数,让你通过下面两种操作,把它们转换为同一个数.求最少的操作数. 1.ai = ai*2 2.ai = ai/2 (向下取整) analyse: 基本思路:首先枚举出每个数能够到达的数字并且记录下到达该数组需要的步数,然后从到达次数为n次的数字中选择步数最小的即为答案. 对于一个数字Ai,它可以变换得到的数字可…

A. Array 题目连接: http://www.codeforces.com/contest/300/problem/A Description Vitaly has an array of n distinct integers. Vitaly wants to divide this array into three non-empty sets so as the following conditions hold: The product of all numbers in the…

time limit per test: 1 second memory limit per test: 256 megabytes input: standard input output: standard output Ayoub had an array aaa of integers of size nnn and this array had two interesting properties: All the integers in the array were between…

题目链接: http://codeforces.com/problemset/problem/498/C C. Array and Operations time limit per test1 secondmemory limit per test256 megabytes 问题描述 You have written on a piece of paper an array of n positive integers a[1], a[2], ..., a[n] and m good pair…

传送门:http://codeforces.com/contest/1108/problem/E2 E2. Array and Segments (Hard version) time limit per test 2 seconds memory limit per test 256 megabytes input standard input output standard output The only difference between easy and hard versions i…

题目链接:http://codeforces.com/problemset/problem/507/B 题目意思:给出圆的半径,以及圆心坐标和最终圆心要到达的坐标位置.问最少步数是多少.移动见下图.(通过圆上的边固定转动点,然后转动任意位置,圆心就会移动了,这个还是直接看图吧) 解题的思路就是,两点之间,距离最短啦----要想得到最少步数,我们需要保证圆心在这条连线上移动,每次转动的角度是180度,而每步移动的距离是2r,直到两个圆交叉,要注意最后一步转动的角度可能会小于180度.最后就是注意精…

题目链接:http://codeforces.com/problemset/problem/295/A 我的做法,两次线段树 #include <cstdio> #include <cstring> const int N = 100005; long long sumv[N * 3]; long long add[N * 3]; long long a[N]; struct opera { int l, r; long long d; } op[N]; void pushdown…

Codeforces 洛谷:咕咕咕 CF少有的大数据结构题. 思路 考虑一些欧拉函数的性质: \[ \varphi(p)=p-1\\ \varphi(p^k)=p^{k-1}\times (p-1)=p^k \times \frac{p-1}{p},k>0\\ \varphi(ab)=\varphi(a)\varphi(b),gcd(a,b)=1\\ \dots \] 有上面三个就够了. 要求 \[ \varphi(\prod a_i) \] 可以考虑把\(\prod a_i\)拆成 \[ \p…

Please, another Queries on Array? 利用欧拉函数的计算方法, 用线段树搞一搞就好啦. #include<bits/stdc++.h> #define LL long long #define fi first #define se second #define mk make_pair #define PLL pair<LL, LL> #define PLI pair<LL, int> #define PII pair<int, i…

题目链接:A Leapfrog in the Array 题意:给出1-n的n个数,从小到大每隔一个位置放一个数.现在从大到小把数往前移动,每次把最右边的数移动最靠右边的空格处直到n个数都在前n个位置. 题解:从数据的大小就可以看出这题一定是推公式的题,那么假设现在一个数刚刚移动到了x位置,那么这个数之前一定有x/2个数没有移动过,所有这个数后面就有n-x/2个数(这里包括x本身).所以x在移动之前的位置就是x+(n-x/2).所以一直将所要求的x 按 x =  x+(n-x/2)这个公式一直向…

点击打开链接 Amr and Chemistry time limit per test 1 second memory limit per test 256 megabytes input standard input output standard output Amr loves Chemistry, and specially doing experiments. He is preparing for a new interesting experiment. Amr has n di…

D. Little Elephant and Array time limit per test 4 seconds memory limit per test 256 megabytes input standard input output standard output The Little Elephant loves playing with arrays. He has array a, consisting of n positive integers, indexed from…

Codeforces 558C 题意:给n个数字,对每一个数字能够进行两种操作:num*2与num/2(向下取整),求:让n个数相等最少须要操作多少次. 分析: 计算每一个数的二进制公共前缀. 枚举法亦可. /* *Author : Flint_x *Created Time : 2015-07-22 12:33:11 *File name : whust2_L.cpp */ #include<iostream> #include<sstream> #include<fstr…

Amr loves Geometry. One day he came up with a very interesting problem. Amr has a circle of radius r and center in point (x, y). He wants the circle center to be in new position (x', y'). In one step Amr can put a pin to the border of the circle in a…

C. Hard Process time limit per test 1 second memory limit per test 256 megabytes input standard input output standard output You are given an array a with n elements. Each element of a is either 0 or 1. Let's denote the length of the longest subsegme…

http://codeforces.com/contest/220/problem/B 题意:给出一个数组,给出m组询问,问区间中出现a[i] 次的有多少个. sl: 很显然的离线问题了. 大视野菜花的加强版. 可以这么搞,假设当前走到了a 看看之前是不是有a个a有的话就在a-k处 减1 同时补上上次的操作就行.具体键代码. http://codeforces.com/contest/220/submission/6948720…

B. A Leapfrog in the Array time limit per test 2 seconds memory limit per test 512 megabytes input standard input output standard output Dima is a beginner programmer. During his working process, he regularly has to repeat the following operation aga…

t题目链接:http://codeforces.com/contest/1291/problem/B 思路: 用极端的情况去考虑问题,会变得很简单. 无论是单调递增,单调递减,或者中间高两边低的情况都可以变为三种模型. (1)0,1,2,3,4........n-3,n-2,n-1 (2)n-1,n-2,n-3.....3,2,1,0 (3)0,1,2,3,4,.....n.......4,3,2,1,0 那么,我们只需要查看当前位置是否大于等于极端模型(3)在这个位置的数值,如果当前位置不满足…

一个人只要存在债务关系,那么他的债务可以和这整个债务关系网中任何人连边,和他当初借出或欠下的人没有关系.只需要记录他的债务值即可. #define HAVE_STRUCT_TIMESPEC #include<bits/stdc++.h> using namespace std; ]; vector<array<> >v; int main(){ ios::sync_with_stdio(false); cin.tie(NULL); cout.tie(NULL); lon…