Popular Cows Time Limit: 2000MS   Memory Limit: 65536K Total Submissions: 37111   Accepted: 15124 Description Every cow's dream is to become the most popular cow in the herd. In a herd of N (1 <= N <= 10,000) cows, you are given up to M (1 <= M &…

Popular Cows Time Limit: 2000MS   Memory Limit: 65536K Total Submissions: 37083   Accepted: 15104 Description Every cow's dream is to become the most popular cow in the herd. In a herd of N (1 <= N <= 10,000) cows, you are given up to M (1 <= M &…

We give the following inductive definition of a “regular brackets” sequence: the empty sequence is a regular brackets sequence, if s is a regular brackets sequence, then (s) and [s] are regular brackets sequences, and if a and b are regular brackets…

Going from u to v or from v to u? Time Limit: 2000MS   Memory Limit: 65536K Total Submissions: 15494   Accepted: 4100 Description In order to make their sons brave, Jiajia and Wind take them to a big cave. The cave has n rooms, and one-way corridors…

http://poj.org/problem?id=2186 首先求出所有的强连通分量,分好块.然后对于每一个强连通分量,都标记下他们的出度.那么只有出度是0 的块才有可能是答案,为什么呢?因为既然你有了出度,那么就是指向了另外一个块,那么你就不能指望那个块也指向你了,因为这样会形成环,所以肯定有一个块的cow不支持你,所以你这个块就不会是popular cow 那么就有两种情况, ①.出度是0的块的个数是1个,那么就是唯一的答案. ②.出度是0的快的个数有多个,那么答案是0, 因为至少也有一个…

好久没写过这么长的代码了,题解东哥讲了那么多,并查集优化还是很厉害的,赶快做做前几天碰到的相似的题. #include <iostream> #include <algorithm> #include <cstdio> using namespace std; , M = 2e5 + ; ], Next[M * ]; int dfn[N], low[N], n, m, tot, num; ]; void add(int x, int y) { ver[++tot] =…

蕾姐讲过的例题..玩了两天后才想起来做 貌似省赛之后确实变得好懒了...再努力两天就可以去北京玩了! 顺便借这个题记录一下求强连通分量的算法 1 只需要一次dfs 依靠stack来实现的tarjan算法 每次走到一个点 马上把它压入栈中 每次对与这个点相连的点处理完毕 判断是否low[u]==dfn[u] 若是 开始退栈 直到栈顶元素等于u才退出(当栈顶元素等于u也需要pop) 每次一起退栈的点属于同一个强连通分量 储存图可以用链式前向星也可以用邻接矩阵更可以用vector 蕾姐说不会超时 我信…

题意:有N只奶牛,奶牛有自己认为最受欢迎的奶牛.奶牛们的这种“认为”是单向可传递的,当A认为B最受欢迎(B不一定认为A最受欢迎),且B认为C最受欢迎时,A一定也认为C最受欢迎.现在给出M对这样的“认为...”的关系,问有多少只奶牛被除其本身以外的所有奶牛关注. 思路:既然有单向传递关系,那么关系图可能就形成了环,一个环内的奶牛互相认为.如果把这些环用一个点代替的话,建反图,就成了一个有向无环图了,直接遍历求出入度为0的点有多少个子节点就可以了. #include<stdio.h> #inclu…

Going from u to v or from v to u? Time Limit: 2000MS   Memory Limit: 65536K Total Submissions: 17383   Accepted: 4660 Description In order to make their sons brave, Jiajia and Wind take them to a big cave. The cave has n rooms, and one-way corridors…

Going from u to v or from v to u? Time Limit: 2000MS   Memory Limit: 65536K Total Submissions: 19234   Accepted: 5182 Description In order to make their sons brave, Jiajia and Wind take them to a big cave. The cave has n rooms, and one-way corridors…