2016 大连网赛---Function(单调栈)】的更多相关文章

题目链接 http://acm.split.hdu.edu.cn/showproblem.php?pid=5875 Problem Description The shorter, the simpler. With this problem, you should be convinced of this truth.    You are given an array A of N postive integers, and M queries in the form (l,r). A fu…
题目链接 http://acm.split.hdu.edu.cn/showproblem.php?pid=5869 Problem Description This is a simple problem. The teacher gives Bob a list of problems about GCD (Greatest Common Divisor). After studying some of them, Bob thinks that GCD is so interesting.…
题目链接 http://acm.split.hdu.edu.cn/showproblem.php?pid=5877 Problem Description You are given a rooted tree of N nodes, labeled from 1 to N. To the ith node a non-negative value ai is assigned.An ordered pair of nodes (u,v) is said to be weak if  (1) u…
//大连网赛 1007 Friends and Enemies // 思路:思路很棒! // 转化成最大二分图 // 团:点集的子集是个完全图 // 那么朋友圈可以考虑成一个团,原题就转化成用团去覆盖怎样最多.团至少是2个点,所以就是n*n/4 #include <bits/stdc++.h> using namespace std; #define LL long long typedef pair<int,int> pii; const double inf = 1234567…
Problem Description YJQQQAQ has an array A of length n. He defines a function fl,r,k where l,r,k are positive integers that satisfies l≤r and r×k≤n, and the value of the function equals to p×q×⌊k√⌋ where p equals to the sum value of Al×k,A(l+1)×k,...…
Function Time Limit: 7000/3500 MS (Java/Others)    Memory Limit: 262144/262144 K (Java/Others) Problem Description The shorter, the simpler. With this problem, you should be convinced of this truth.    You are given an array A of N postive integers,…
题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=5876 题意:给定一个图(n个顶点m条边),求其补图最短路 思路:集合a表示当前还未寻找到的点,集合b表示本次bfs之后仍未寻找到的点 #include<cstdio> #include<set> #include<queue> #include<cstring> using namespace std; const int N = 2e5 + 5; set &l…
[CF815D]Karen and Cards 题意:一张卡片有三个属性a,b,c,其上限分别为A,B,C,现在有n张卡片,定义一张卡片能打败另一张卡片当且仅当它的至少两项属性要严格大于另一张的对应属性.问在所有可能的卡片中,有多少种能打败这全部n张卡. n,A,B,C<=500000 题解:我们反过来,统计哪些卡片不能打败全部的卡. 我们先确定一个属性c,那么对于某张卡片(ai,bi,ci),如果c<=ci,则要求!(a>ai&&b>bi):如果c>ci,则…
LeetCode 84. Largest Rectangle in Histogram 单调栈应用 leetcode+ 循环数组,求右边第一个大的数字 求一个数组中右边第一个比他大的数(单调栈 LeetCode--寻找数组中第三大的数…
枚举每个点作为次大值,用单调栈处理出左边 / 右边第一个比它大的数,直接回答 复杂度$O(n)$ #include <cstdio> #include <cstring> #include <iostream> using namespace std; extern inline char gc() { ], *S = RR + , *T = RR + ; , , stdin), S = RR; return *S ++; } inline int read() { ,…