Problem Description A sequence consisting of one digit, the number 1 is initially written into a computer. At each successive time step, the computer simultaneously tranforms each digit 0 into the sequence 1 0 and each digit 1 into the sequence 0 1.…

题意: 有很多台机器,可以把物件从一种状态改装成另一种状态,初始全为\(0\),最终状态全为\(1\),让你可以拼凑机器,请问最大总性能为多少,且要求输出方案. 题解: 这道题是真的水啊,我不想写太多,加一点吧.我们发现,把一个机器当作点来看的话一个机器的加工数即为点权.而点权在网络流的题目里是\(SB\),于是考虑转化为边权.而且我们要控制流量,于是考虑进行拆点. 把点拆开后,因为初始是全为\(0\)的,所以将所有初始状态为\(0\)的机器的入点与超级源点连边,而所有最终状态为\(1\)的机器…

题目大意:有n个网站,由m条线路相连,每条线路都有一定的花费,找出连接所有线路的最小花费. 最小生成树问题(Minimal Spanning Tree, MST),使用Kruskal算法解决. #include <cstdio> #include <vector> #include <algorithm> using namespace std; typedef pair<int, int> ii; #define MAXN 1000100 int p[MA…

题目地址:https://codeforces.com/contest/1136 A: Nastya Is Reading a Book 题解:挨个判断即可,水题. 参考代码: #include<bits/stdc++.h> using namespace std; ],r[],k; int main() { scanf("%d",&n); ;i<=n;++i) scanf("%d%d",&l[i],&r[i]); scan…

Network Time Limit: 5000MS   Memory Limit: 65536K Total Submissions: 13172   Accepted: 4774 题目链接:http://poj.org/problem?id=3694 Description: A network administrator manages a large network. The network consists of N computers and M links between pair…

Network Time Limit: 10000/5000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 1014    Accepted Submission(s): 206 Problem Description A network administrator manages a large network. The network consists of N comput…

题目链接:https://vjudge.net/problem/POJ-3694 A network administrator manages a large network. The network consists of N computers and M links between pairs of computers. Any pair of computers are connected directly or indirectly by successive links, so d…

题目链接:https://vjudge.net/problem/HDU-4738 A network administrator manages a large network. The network consists of N computers and M links between pairs of computers. Any pair of computers are connected directly or indirectly by successive links, so d…

概念: 双连通分量有点双连通分量和边双连通分量两种.若一个无向图中的去掉任意一个节点(一条边)都不会改变此图的连通性,即不存在割点(桥),则称作点(边)双连通图. 一个无向图中的每一个极大点(边)双连通子图称作此无向图的点(边)双连通分量.求双连通分量可用Tarjan算法.--百度百科 Tip:先学一下tarjan算法以及求割点割边的算法之后,再看会比较好理解一些. 点双连通和边双连通 连通的概念:在无向图中,所有点能互相到达 连通分量:互相联通的子图 点双连通:删掉一个点之后,图仍联通 边双连…

Network Time Limit: 5000MS   Memory Limit: 65536K Total Submissions: 8669   Accepted: 3175 Description A network administrator manages a large network. The network consists of N computers and M links between pairs of computers. Any pair of computers…