continue: def func(): for i in range(1,11): if i % 2 == 0: continue # 作用是当符合上面的if判语句后,就直接跳过之后的语句,也就是不执行print(i) print (i) func() # 输出的结果是:1,3,5,7,9 break def func1(): for i in range(1,11): if i % 2 == 0: break # 作用是不满足if语句后,直接执行print(i) print (i) fun…
continue continue 语句跳出本次循环,而break跳出整个循环. continue 语句用来告诉Python跳过当前循环的剩余语句,然后继续进行下一轮循环. continue语句用在while和for循环中. # continue第一个实例 for letter in 'Python': if letter == 'h': continue print('当前字母 :', letter) > 当前字母 : P > 当前字母 : y > 当前字母 : t > 当前字母…
zjzc01:/root/test# cat a3.pl sub mask { my $n=shift; my $j =100; for ($i = 1;$i <= 5;$i++){ print "\$i is $i\n"; while ($n=$n+1) { $j++; print "\$n is $n\n"; if ($n==10){print "\$n---end is $n\n";$n=0;last}; }} }; &mas…
Given a string s and a dictionary of words dict, determine if s can be segmented into a space-separated sequence of one or more dictionary words. For example, givens = "leetcode",dict = ["leet", "code"]. Return true because &…
Given a string s and a dictionary of words dict, determine if s can be segmented into a space-separated sequence of one or more dictionary words. For example, givens = "leetcode",dict = ["leet", "code"]. Return true because &…
Given a string s and a dictionary of words dict, determine if s can be break into a space-separated sequence of one or more dictionary words. Example Given s = "lintcode", dict = ["lint", "code"]. Return true because "li…
Work Break I Given a string s and a dictionary of words dict, determine if s can be segmented into a space-separated sequence of one or more dictionary words. For example, givens = "leetcode",dict = ["leet", "code"]. Return t…
Problem link: http://oj.leetcode.com/problems/word-break/ We solve this problem using Dynamic Programming method. Let A[0..n-1] be a boolean array, where A[i]=True if and only if s[i..n-1] can be segmented into words. The recursive formula is: A[i] =…
Given a string s and a dictionary of words dict, determine if s can be segmented into a space-separated sequence of one or more dictionary words. For example, givens = "leetcode",dict = ["leet", "code"]. Return true because &…
https://leetcode.com/problems/word-break/ Given a string s and a dictionary of words dict, determine if s can be segmented into a space-separated sequence of one or more dictionary words. For example, givens = "leetcode",dict = ["leet"…